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andrew11 [14]
4 years ago
5

Which of these components is present in this circuit schematic?

Physics
2 answers:
Alchen [17]4 years ago
7 0

Answer:

the answer is d for plato users

Explanation:

Svetlanka [38]4 years ago
4 0
Its resistor :}...............

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Assume that charge −q−q-q is placed on the top plate, and +q+q+q is placed on the bottom plate. What is the magnitude of the ele
STatiana [176]

Answer:

Magnitude of electric field = E = q/Aε0

Explanation:

Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:

                                          q = CV

And  

                                          V = q/C    ……. (i)

The capacitance is given by the following equation:  

                                         C = Aε0/d ……. (ii)

Put equation (ii) in (i) ,

                                          V = qd/ Aε0 …..(iii)    

The electric field is defined as:  

                                            E = V/d   …… (iv)

Put equation (iii) in (iv),

                                            E = qd/ Aε0d

                                            E = q/Aε0

Hence, the magnitude of electric field will be q/Aε0 .

                                         

8 0
3 years ago
Whats the value of 1,152 Btu in joules?(a)1,964,445J(b)1,215,360J(c)2,485,664J(d)997,875J
Anvisha [2.4K]
In order to make any headway with this one, it might help
to know how many joules there are in one BTU, ya reckon ?

I went and looked it up on line, you're welcome.

       1 BTU  =  1055.06 joules .

So if you happen to have 1,152 BTU of energy,
there are 1055.06 joules in each one of them,
and the total is

                        (1,152 BTU) x (1,055.06 joule/BTU)

                   =          1,215,429.12 joules .

Scanning the choices for anything close, we notice that choice-'b'
is only about 0.006% less than my answer.  So that must be the one
they're fishing for, and they must have used 1055-even for their
conversion factor.
8 0
3 years ago
Read 2 more answers
True or False
devlian [24]

Answer:

true

Explanation:

Hope it helped you brainiest plz

4 0
3 years ago
Read 2 more answers
Two points charge of 4\mu C and 2\mu C are placed at theopposite corners of a rectangle. What is the potential difference Va- Vb
bulgar [2K]

Answer:

Va-Vb=168KV

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\sqrt{0.3^2+0.4^2} =0.5

at  opposite sides

Mathematically Va can represented as

Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )

Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )

Va =9*10^9(0.00001333333-0.000004} )

Va =84000V

Va =84KV

Mathematically Vb is  represented as

Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )

Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )

Va =9*10^9(-0.00001333333+0.000004} )

Va =-84000V

Va =-84KV

Therefore

Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV

7 0
3 years ago
Large wind turbines with a power capacity of 8 MW and blade span diameters of over 160 m are available for electric power genera
andriy [413]

Answer:

85413.20177 W

2050.831684248 kWh

184.5748512 dollars

Explanation:

d = Diameter of blade = 100 m

r = Radius = \dfrac{d}{2}=\dfrac{100}{2}=50\ m

\eta = Efficiency = 0.34

\rho = Density of air = 1.25 kg/m³

V = Velocity of wind = 8 m/s

A = Area = \pi r^2

The power of a wind turbine is given by

P=\dfrac{1}{2}\rho AV^3\eta\\\Rightarrow P=\dfrac{1}{2}\times 1.25\times \pi\times 50^2\times 8^3\times 0.34\\\Rightarrow P=854513.20177\ W

The power is 85413.20177 W

Energy is given by

E=Pt\\\Rightarrow E=854513.20177\times 24\\\Rightarrow E=20508316.84248\ Wh\\\Rightarrow E=2050.831684248\ kWh

The energy is 2050.831684248 kWh

The revenue is given by

0.09\times 2050.831684248=184.5748512\$

The revenue generated is 184.5748512 dollars

6 0
3 years ago
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