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4 years ago

The air sealed between two panes of glass in some windows helps to _____.

Physics

2 answers:

Crank4 years ago

4 0

Answer:

Insulate

Explanation:

Air is a good insulator.

Insulators are the materials which do not allow the heat to pass through them. Some examples of insulators are plastic, rubber, styrofoam, air, etc.

Air is trapped between the two layers of glass. Here air works as an insulator and do not allow to pass the hotness or coldness through them, die to which the temperature inside the plane remains constant.

olga_2 [115]4 years ago

3 0

<span>The air sealed between two panes of glass in some windows helps to </span><span>insulate and helps it to keep the warmth or coolness inside.

Hope that helps!
-Chris</span>

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3 years ago

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3 years ago

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A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the

xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

$tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2$

$\hat{ECD} = tan^{-1} 2 = 63.43^o$

This is also the angle ACB, so we can find the length AB:

$tan(\hat{ACB}) = \frac{AB}{AC} = \frac{AB}{234}$

$2 = \frac{AB}{234}$

$AB = 2*234 = 468 m$

So the height of the building is 468m

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4 years ago

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

miss Akunina [59]

Answer:

0.07756 m

Explanation:

Given mass of object =0.20 kg

spring constant = 120 n/m

maximum speed = 1.9 m/sec

We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by $v_{max}=A\omega$ where A is amplitude and $\omega$ is angular velocity