We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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F = ma
We have mass = 0.2kg
and acceleration = 20 m/s^2
So..
F = (0.2)(20)
F = 4 N
Answer:
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Explanation:
Distance=20m
time=18s
Initial velocity=0m/s
Final velocity=10m/s
The equation we use to find average velocity is v=d/t (average velocity=distance/time)
V=20m/18s
V (average velocity)=1.11m/s
Answer: Please see the attachments below
Explanation: Please see the attachments below