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Vilka [71]
3 years ago
10

How much heat is required to heat 0.1 g of ∆hvap =2260 j/g ∆h =340j/g fus iceat−30ctosteamat100c? use the approximate values?

Physics
1 answer:
Anestetic [448]3 years ago
7 0
How much heat<span> is </span>required<span> to </span>heat 0.1 g<span> of </span>∆hvap<span> =</span>2260 j/g ∆h<span> =</span>340j/g fus iceat−30 ctosteamat 100c?use<span> the </span>approximate values<span>?</span>
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A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from
valina [46]

The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

<h3>Path of the bowling ball</h3>

Based on the law of inertia, which is the reluctance of an object to stop moving once in motion or start moving when it is at rest.

The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.

Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

Learn more about horizontal direction here: brainly.com/question/2534565

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3 0
2 years ago
Why do the noble gases and some other elements on the right side of the periodic table occur as gases instead of solids as do th
mash [69]

Explanation:

The left side of the periodic table has elements that have less number of electrons in the valence shell.

These elements loose electrons easily.These elements appear as metals or metalloids in nature.These are hard solids.Their inter molecular forces are very strong.

The right side of the periodic table has elements that have more number of electrons in the valence shell.

These elements gain electrons easily.These elements appear as non metals most of which are gases.Their inter molecular forces are weak.

8 0
3 years ago
A point charge with charge q1 = 3.40 μC is held stationary at the origin. A second point charge with charge q2 = -4.90 μC moves
expeople1 [14]

Answer:

-0.79 J

Explanation:

We are given that

q_1=3.4\mu C=3.4\times 10^{-6} C

1\mu C=10^{-6} C

q_2=-4.9\mu C=-4.9\times 10^{-6} C

x_1=0.125,y_1=0

x_2=0.280,y_2=0.235

We have to find the work done by the electric force on the moving point charge.

r_1=\sqrt{x^2_1+y^2_1}=\sqrt{(0.125)^2+0}=0.125

r_2=\sqrt{(0.280)^2+(0.235)^2}=0.366

Work done,W=kq_1q_2(\frac{1}{r_1}-\frac{1}{r_2})

Where k=9\times 10^9

Using the formula

W=9\times 10^9\times 3.4\times 10^{-6}\times(-4.9\times 10^{-6})(\frac{1}{0.125}-\frac{1}{0.366})

W=-0.79 J

5 0
3 years ago
Which of the following describes resistance force?
ehidna [41]
Hiiiii friends......
here is your answer.....


✌✌ Resistive force is a force where direction is opposite to the velocity of body or the sum of the other force and may refer to friction

now force lost by the machine
4 0
3 years ago
A bird uses 10 N of force to pull a worm out of the ground a distance of 3 inches. How much work did the bird do?
pochemuha

Answer:

The work done by the bird is 0.762 J

Explanation:

Given;

force applied by the bird, f = 10 N

distance the bird moved the worm, d = 3 inches = 0.0762 m

The work done by the bird is given by;

W = F x d

where;

W is the work done by the bird

d is the distance the bird moved the load

Substitute the given values and estimate the work done by the bird;

W = 10 x 0.0762

W = 0.762 J

Therefore, the work done by the bird is 0.762 J

6 0
3 years ago
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