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yuradex [85]
3 years ago
6

How much heat is required to change the temperature of a 15 g aluminum can with 100 g of water from 24.5°C to 55°C?

Chemistry
1 answer:
Assoli18 [71]3 years ago
3 0
Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium 
Heat gained by water = 100 × 4.186 × 30.5 
                                   = 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5 
                                          = 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules
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Alexxandr [17]
1s, 2s, 3s, 3d, 3p. huehueheuheuehuehue

4 0
3 years ago
How many grams are in 3.4 moles of C2H5OH molecules? (use molar mass and round answer to the correct number of sig figs)
Salsk061 [2.6K]
Molar mads of C2H5OH:
12*2+1*5+16+1
24+5+17
46
no of moles = mass in grams/molar mass
3.4=m/46
3.4*46=m
m=156.4
m=156g
5 0
3 years ago
Calculate the percent of Cl in KClO4
sergejj [24]

Answer:

25.6 %.

Explanation:

  • To calculate the % of Cl in KClO₄:

<em>% Cl = [Atomic mass of (Cl)/molar mass of KClO₄] x 100</em> = [(35.5 g/mol)/(138.55 g/mol)] x 100 = <em>25.62 % ≅ 25.6 %.</em>

7 0
4 years ago
Consider the following balanced equation:
kow [346]

Answer:

The theoretical yield of Cu(s) in moles is 60.15 moles

Explanation:

Step 1: Data given

Number of moles CuO = 70.8 moles

Number of moles NH3 = 40.1 moles

Molar mass CuO = 79.545 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles

There will remain 70.8 - 60.15 = 10.65 moles CuO

Step 3: Calculate moles Cu

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

For 40.1 moles NH3 we'll have 60.15 moles Cu

The theoretical yield of Cu(s) in moles is 60.15 moles

8 0
4 years ago
What is the temperature change if 400 J of energy is added to 10 grams of water
Gemiola [76]

The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

<h3>How to calculate temperature change?</h3>

The temperature change of a calorimeter can be calculated using the following expression:

E = mc∆T

Where;

  • E = energy in joules
  • m = mass
  • c = specific heat capacity = 4.18J/g°C
  • ∆T = change in temperature

400 = 10 × 4.18 × ∆T

400 = 41.8∆T

∆T = 400/41.8

∆T = 9.57°C

Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

Learn more about change in temperature at: brainly.com/question/11464844

3 0
3 years ago
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