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2 years ago

How much heat is required to change the temperature of a 15 g aluminum can with 100 g of water from 24.5°C to 55°C?

1 answer:

3 0

Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium
Heat gained by water = 100 × 4.186 × 30.5
= 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5
= 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules

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Calculate 4572cm to meters

9966 [12]

Answer:

45.72meters

Explanation:

8 0

3 years ago

A chemist has one solu6on that is 40% sulfuric acid and one that is 10% sulfuric acid. How much of each should she use to make 2

kipiarov [429]

Answer:

12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.

Explanation:

For first solution of sulfuric acid :

C₁ = 40% , V₁ = ?

For second solution of sulfuric acid :

C₂ = 10% , V₂ = ?

For the resultant solution of sulfuric acid:

C₃ = 28% , V₃ = 20L

Also,

V₁ + V₂ = V₃ = 20L ......................................(1)

Using

C₁V₁ + C₂V₂ = C₃V₃

40×V₁ + 10×V₂ = 28×20

So,

40V₁ + 10V₂ = 560........................................(2)

Solving 1 and 2 as:

V₂ = 20 - V₁

Applying in 2

40V₁ + 10(20 - V₁) = 560

40V₁ + 200 - 10V₁ = 560

30V₁ = 360

V₁ = 12 L

So,

V₂ = 20 - V₁ = 8L

12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.

4 0

3 years ago

6. STATEANSWERIN SIG FIGSOR g/cm3. What mass of silver in grams (g) would be required to cover a dimensions of 120.0 ft x 60.0 f

kogti [31]

Answer:

$7.0643\times 10^8 grams$ of silver would be required.

Explanation:

Dimensions of silver mas :

Length = l = 120.0 ft

breadth = b = 60.0 ft

Height = h = 0.33 ft

Volume of silver mass ,V= l × b × h

$V=120.0 ft\times 60.0ft\times 0.33 ft=2,376 ft^3=67,278,816 cm^3$

$1ft^3=28316.8 cm^3$

Density of silver,d = $10.5 g/cm^3$

$Mass = Density\times Volume$

$m=10.5 g/cm^3\times 67,278,816 cm^3=7.0643\times 10^8 g$

$7.0643\times 10^8 grams$ of silver would be required.

7 0

2 years ago

Which of these materials has the highest specific heat?

scoundrel [369]

Iron has the highest specific heat

5 0

3 years ago

Read 2 more answers

How many liters of wine can be held in a wine barrel whose capacity is 22.0 gal?

Ivenika [448]

Answer:

83.3 L

Explanation:

Step 1: Given data

Capacity of the wine barrel (V): 22.0 gal

Step 2: Calculate how many liters of wine can be held in the barrel

To calculate the number of liters of wine that can be held in the barrel, we need to convert 22.0 gal to liters. We will use the conversion factor 1 gal = 3.79 L.

22.0 gal × 3.79 L/1 gal = 83.3 L

8 0

2 years ago