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Licemer1 [7]
3 years ago
9

Ammonia is an important compound used in the production of frertilizer. Below is the chemical equation for producing ammonia fro

m nitrogen and hydrogen
N2+3H2->2NH2

Fill in the blanks with the appropriate numbers for this equation:
___molecule(s) of nitrogen and ___ molecule(s) of hydrogen react with each other to form __ molecule(s) of ammonia.
Chemistry
1 answer:
insens350 [35]3 years ago
3 0

Answer:

6.02×10²³ molecules of nitrogen and 1.20×10²⁴ molecules of hydrogen react with each other to form 1.80×10²⁴ molecules of ammonia.

Explanation:

Reaction is:

N₂  +  3H₂  → 2NH₂

1 mol of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

1 mol = 6.02×10²³ (NA) molecules

2 moles =  2NA → 1.20×10²⁴ molecules

3 moles = 3NA → 1.80×10²⁴ molecules

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2 years ago
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How many moles of H2 and N2 can be formed by the decomposition of 0.145 mol of ammonia, NH3 ?​
zepelin [54]

Answer:

Explanation:

The moles of H2 and N2 are as follows respectively, 0.3915mol of H2 and 0.1305 mol of N2.

5 0
2 years ago
Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH₄), by the following process:
kykrilka [37]

Answer:

6.75 g of HCN can be produced by the reaction

Explanation:

Complete reaction is:

2NH₃ (g) + 3O₂ (g) + 2CH₄ (g) → 2HCN (g) + 6H₂O (g)

Let's determine the moles of each reactant:

11.5 g . 1mol / 17g = 0.676 moles of ammonia

12 g . 1 mol / 32g = 0.375 moles of oxygen

10.5 g . 1mol/ 16 g =  0.656 moles of methane

Now is all about rules of three:

2 moles of ammonia reacts with 3 moles of O₂ and 2 moles of methane

0.676 moles of NH₃ may react with:

(0.676 . 3) /2 = 1.014 moles of O₂

(0.676 . 2) / 2 = 0.676 moles of methane

Both can be the limiting reactant.

3 moles of O₂ react with 2 moles of NH₃ and 2 moles of methane

0.375 moles of O₂ will react with:

(0.375 .2) / 3  = 0.375 moles

The same amount for methane, 0.375 moles

2 moles of CH₄ reacts with 3 moles of O₂ and 2 moles of NH₃

0.656 moles of methane would react with 0.656 moles of NH₃

(0.656 . 3 ) /2 = 0.437 moles of O₂   I do not have enough O₂

Oxygen is the limiting reactant → We can work with the reaction now.

Ratio is 3:2. 3 moles of oxygen produce 2 moles of cyanide

0.375 moles of O₂ may produce (0.375 .2 ) / 3 = 0.250 moles

If we convert the moles to mass → 0.250 mol . 27 g / 1mol = 6.75 g

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3 years ago
Help help help.
Whitepunk [10]
I think B
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MArishka [77]

There are 4 atoms of sodium in the formula of sodium sulfite.

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