Answer:
The amount of NO₂ that can be produced 8.533 g
Explanation:
According to question
2 NO(g) + O₂(g) → 2 NO₂(g)
Given
Moles of nitrogen monoxide = 0.377
Moles of oxygen = 0.278
Since 'NO' is the limiting reagent according to this ratio.
According to equation
2 moles NO reacts to form 2 moles NO₂
So, 0.1855 moles NO give = 0.1855 moles of NO₂
Mass of 1 mole NO₂ = 46 g/mole
Mass of 0.1855 moles = 46 x 0.1855 = 8.533 g
The volume of the liquid in this diagram shown above would be equal to 36.5 mL.
<h3>What is a
graduated cylinder?</h3>
A graduated cylinder is also known as measuring cylinder and it can be defined as a narrow, cylindrical piece of laboratory equipment with marked lines, which are used to measure the volume of a liquid.
In order to take a reading for the measurement of the volume of a liquid such as water, you should ensure that your eye level is even with the center of the meniscus.
In this scenario, the volume of the liquid in this diagram would be 36.5 mL because each of the small lines on the graduated cylinder measures 0.5 mL.
Read more on graduated cylinder here: brainly.com/question/24869562
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+1
Explanation:
To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.
The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit
The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.
The algebraic sum of all oxidation number of atoms in a neutral compound is zero;
The radical NO₃ has a formal charge of -1;
let the oxidation number of Li = x
x + (-1) = 0
x = + 1
learn more:
Oxidation number brainly.com/question/10017129
#learnwithBrainly
Answer:
~1.5 g/cm3 and it does NOT float in water.
Explanation:
If you look at the graph, Object A weighs ~6 grams and is ~4 cm3 in volume
Density = Mass/Volume
So 6 grams/4 cm3 = 1.5 g/cm3
Water has a density of 1 g/cm3 and because Object A density is higher than that of water, it sinks.
:)
