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2 years ago

A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.

Physics

2 answers:

frozen [14]2 years ago

6 0

Answer:

not sure lol

Explanation:

ummmmmm look it up on peersanswer.com

horrorfan [7]2 years ago

3 0

Well, the acceleration is the difference of speeds divided by the time period. $\frac{32.4}{0.5}=64.8rev/s^2$ .
One rev/s is $2\pi rad/s^2$ , so our final result is $64.8*2\pi=407.15rad/s^2$ .

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3 years ago

Find the potential inside and outside a uniformly charged solid sphere whose radius is R and whose total charge is q. Use infini

amid [387]

Answer:

Recall that the electric field outside a uniformly charged solid sphere is exactly the same as if the charge were all at a point in the centre of the sphere:

$E_{outside} =\frac{1}{4\pi(e_{0})}\frac{Q}{r^{2} } r^{'}$

lnside the sphere, the electric field also acts like a point charge, but only for the proportion of the charge further inside than the point r:

$E_{inside} =\frac{1}{4\pi(e_{0})}\frac{Q}{R^{2} } \frac{r}{R} r^{'}$

To find the potential, we integrate the electric field on a path from infinity (where of course, we take the direct path so that we can write the it as a 1 D integral):

$V(r>R)=\int\limits^r_\infty {\frac{1}{4\pi(e_{0)} }\frac{Q}{r^2} } \, dr=\frac{q}{4\pi(e_{0)} } \frac{1}{r} \\V(r$

= $\frac{q}{4\pi e_{0} } [\frac{1}{R} -\frac{r^{2}-R^{2} }{2R^{3} } ]$

∴NOTE: Graph is attached

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3 years ago

What if is a forecasting game, below are actions on your document and all you have to do is predict what will happen after the a

Talja [164]

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2 years ago

Read 2 more answers

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ss7ja [257]

Answer:

Kelvin

Explanation:

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3 years ago

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tamaranim1 [39]

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