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4 years ago

What are the steps used in the scientific method?

1 answer:

7 0

1) make an observation
2)form a question
3)form a hypothesis
4)conduct an experiment
5) analyse the data and draw a conclusion

You might be interested in

How many atoms are in 1.75 mol CHCL3

vaieri [72.5K]

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

6 0

3 years ago

Read 2 more answers

5. Write the names of the following ions.

Talja [164]

A.) Phosphate ion or Orthophosphate
d.) Hydroxide
D.) Ammonium
e.) Iron
C.) Nitrate
f.) Sulfur dioxide

5 0

2 years ago

If 2.27 moles of bromine react with excess phosphorus, how many moles of phosphorus tribromide will be produced

zalisa [80]

Answer:

The answer to your question is 1.51 moles of PBr₃

Explanation:

Data

moles of Br = 2.27

moles of PBr₃ = x

Balanced chemical reaction

2P + 3Br₂ ⇒ 2PBr₃

Reactant Element Products

2 P 2

6 Br 6

-Use proportions to find the answer

3 moles of Br₂ ------------------ 2 moles of PBr₃

2.27 moles of Br₂ ------------------ x

x = (2.27 x 2) / 3

x = 4.54 / 3

x = 1.51 moles

7 0

3 years ago

Read 2 more answers

In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 1.1 MJ, and the work done on th

ratelena [41]

Answer: $\Delta E$ is 1155 kJ

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$ =Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system= $-P\Delta V$ {Work done on the system is positive as the final volume is lesser than initial volume}

w = $13.2kcal=55.2kJ$ (1kcal=4.184 kJ)

q = +1.1 MJ = 1100 kJ (1MJ=1000kJ) {Heat absorbed by the system is positive}

$\Delta E=1100kJ+(55.2)kJ=1155kJ$

Thus $\Delta E$ is 1155 kJ

4 0

3 years ago

Write the TOTAL IONIC EQUATION between zinc and hydrochloric acid.

Andreyy89

Answer : The net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced ionic equation between zinc and hydrochloric acid will be,

$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$

The ionic equation in separated aqueous solution will be,

$Zn(s)+2H^+(aq)+2Cl^-(aq)\rightarrow Zn^{2+}(aq)+2Cl^-(aq)+H_2(g)$

In this equation, $Cl^-$ is the spectator ion.

By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

8 0

4 years ago