Question

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Answer 1

M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!

Answer 2

Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

$M_2$ = molarity of hydrochloric acid = 6 M = 6 mole/L

$V_1$ = volume of concentrated hydrochloric acid = ?

$V_2$ = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

$12mole/L\times V_2=6mole/L\times 0.5L$

$V_2=0.25L$

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters