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Gnom [1K]
2 years ago
11

Suppose a 10.0 mL sample of an unknown

Chemistry
1 answer:
mote1985 [20]2 years ago
6 0

The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

                                               M = \frac{mol}{v}

Thus, to find the molarity of the sample, the following calculations must be performed:

V_f = 10ml + 625ml = > 635ml

                                              \frac{0.004mol}{xmol} =\frac{1000ml}{635ml}

                                                 x = 0.00254 mol

So, 0.00254 moles were added per 10ml, so we can do:

                                              \frac{0.00254mol}{xmol}= \frac{10ml}{1000ml}  \\x = 2.54mol/L

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

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Oksanka [162]

Answer: b) positron

Explanation:

The antiparticle or the antimatter counterpart of the electron is called positron.

The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.

Below is an attachnent that further explains this

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2 years ago
What is the heaviest natural element?​
masha68 [24]

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7 0
3 years ago
A 2.0 mL sample of a liquid has a mass of 44.0 g. What is the density of the liquid?
riadik2000 [5.3K]

Answer:

The answer is

<h2>22 g/mL</h2>

Explanation:

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density =  \frac{mass}{volume}

From the question

mass of liquid = 44 g

volume = 2 mL

The density of the liquid is

density =  \frac{44}{2}

We have the final answer as

<h3>22 g/mL</h3>

Hope this helps you

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