Question

Suppose a 10.0 mL sample of an unknown

Answer 1

The concentration of HCl is equal to 2.54mol/L.

Mole calculation

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

                                               $M = \frac{mol}{v}$

Thus, to find the molarity of the sample, the following calculations must be performed:

$V_f = 10ml + 625ml = > 635ml$

                                              $\frac{0.004mol}{xmol} =\frac{1000ml}{635ml}$

                                                 $x = 0.00254 mol$

So, 0.00254 moles were added per 10ml, so we can do:

                                              $\frac{0.00254mol}{xmol}= \frac{10ml}{1000ml} \\x = 2.54mol/L$

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237