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3 years ago

Alfred pushes on a heavy box, but cannot move it. The box has a lot of _____. inertia motion friction gravity

Physics

1 answer:

77julia77 [94]3 years ago

8 0

Answer:

Inertia

Explanation:

Inertia is best defined as the ability of an object to resist a change in position or movement. That is why when an object has a higher mass, the higher the inertia. Imagine an oncoming truck that is fully loaded versus you. The tendency for the truck to change its movement would be difficult because of its its mass. It has a lot of inertia.

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An electromagnet on the ceiling of an airplane holds a steel ball. When a button is pushed, the magnet releases the ball. The ex

blagie [28]

Answer:

The ball will fall on the X .

Explanation:

At height, when the aeroplane is in great speed , everything attached with it acquires the same speed . So ball will also have the same speed as the aeroplane have. When ball starts falling off , it gets detached from plane but , at the same time it continues to travel with its earlier speed , because of inertia of motion. So it remains stationary with respect to plane in horizontal direction . It has velocity with respect to plane only in vertical direction. Hence it will fall on the X. It is due to first law of motion.

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3 years ago

Which astronomer supported the belief that earth was at the center fo the universe?

MissTica

B. Ptolemy believed that the earth was the center of the universe

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3 years ago

Read 2 more answers

A clock radio is rated as 30 w of power output. if the radio also draws 30 w at 120 v, which will the current draw be?

g100num [7]

P = IV

I = P/V = 30 / 120 = 0.25 A.

Current = 0.25A

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3 years ago

An object with velocity 141 ft/s has a kinetic energy of 1558.71 ftâˆ™lbf, on a planet whose gravity is 31.5 ft/s2. What is its

Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

$K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \ \times \ \ \ \ 1 \ lbf\ }$

$m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm$

Therefore, the mass of the object is 5.045 lbm.

6 0

3 years ago

At time t1 = 14 s, a car is located at 99, 80, 27 m and has velocity 4, 0, −3 m/s. At time t2 = 18 s, what is the position of th

Korvikt [17]

Answer:

115, 80, 15m

Explanation

t1 = 14s

t2 = 18s

change in time = 4s (18-14)

r(final) = r(initial) + (average velocity) x (change in time)

multiply the average velocity with the change in time

= (4, 0, -3) x 4 = 16, 0, -12

now we'll add this value to the initial position of the car

(99, 80, 27)m + (16, 0, -12)m = (115, 80, 15)m

8 0

3 years ago