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Vanyuwa [196]
4 years ago
8

Pls pls pls pls pls help

Physics
1 answer:
Rzqust [24]4 years ago
8 0

Answer:

what grade are you in so i can help

Explanation:

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On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass
Mars2501 [29]

Answer with Explanation:

We are given that

A.Mass,m=12 kg

\theta=53^{\circ}

\mu_k=0.16

Speed,v=1.5m/s

Net force in x direction must be zero

F_{net}=0

Fsin\theta-f=0

Fsin\theta=f

Net force in y direction

N-mg-Fcos\theta=0

N=mg+Fcos\theta

f=\mu_kN=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_kmg+\mu_kFcos\theta

Fsin\theta-\mu_kFcos\theta=\mu_kmg

F(sin\theta-\mu_kcos\theta)=\mu_kmg

F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}

Power,P=Fv

P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v

Where g=9.8m/s^2

B.Substitute the values

P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5

P=40.17W

6 0
4 years ago
When a space shuttle was launched, the astronauts aboard experienced and acceleration of 29.0 m/s. If one of the astronauts had
ankoles [38]

             Net force = (mass) · (acceleration)

                           = (69 kg) · (29 m/s²)

                           = (69 · 29) · (kg·m/s²)

                           =    2,001  Newtons upward
                         (about  450 pounds)
7 0
4 years ago
7. A car is travelling along a road at 30 ms when a pedestrian steps into the road 55 m ahead. The
trasher [3.6K]

Answer: Car collide with man

Explanation:

Given

Speed of car is u=30\ m/s

Distance of the man from the car is s=55\ m

Reaction time t_r=0.5\ s

Rate of deceleration a_d=-10\ m/s^2

Distance traveled in the reaction time d_o=30\times 0.5=15\ m

Net effective distance to cover d=55-15=40\ m

Distance required to stop the car

\Rightarrow v^2-30^2=2(-10)(s)\\\Rightarrow 0-900=-20s\\\Rightarrow s=45\ m

Require distance is more than that of net effective distance. Hence, car collides with the man.

6 0
3 years ago
Select the correct answer.
Vesna [10]

Answer:

A. continental-oceanic convergent

Explanation:

I knew it couldn't be B because it's oceanic and <em>continental</em>, not oceanic and <em>oceanic</em>.

Next, I noticed the word <em>convergent</em>, which implies "coming together" to me.

I looked it up and noticed the term <em>convergent</em> referred to a plate boundary where a plate slips under (<em>subducted</em>) another, so I knew it was A.

Hopefully, this helps you understand the question better. Have a great day!

3 0
3 years ago
A dolphin jumps out of the water. As it falls back down it a clerated at a rate of -9,8m/s^2 for 0.8 seconds of free fall. To ca
Anettt [7]

Answer:

0.196 m

Explanation:

Given in the question that,

time taken by the dolphin to go back to water = 0.2 sec

To solve the question we will use Newton's Law of motion

<h3>S = ut + 0.5(a)t²</h3>

here S is distance covered

u is initial speed

a = acceleration due to gravity

t = time taken

Plug value in the equation above

S = 0(0.2) + 0.5(-9.8)(0.2)²

S = 0.5(-9.8)(0.2)²

S = -0.196 m

Negative sign represent direction

(Assuming that dolphin have a vertical straight jump not a projectile motion)

4 0
3 years ago
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