Imagine a ball is moving on the following horizontal line.
. . . . . . . . . . . . . . . . . . . O. . . . . . . . . . . . . . . . . .
Take right as positive. O is the starting point of the ball. Denote the ball by o.
. . . . . . . . . . . . . . . . . . . O. . . . . . . ... . . o . . . . . .
Assume the ball is moving to the right. It has positive displacement since it is on the right of O, and positive velocity since its positive displacement is increasing.
.ñ
. . . . . . . . . . . . . . . . . . . O. . . . o . . . . . . . . . . . . .
Now the ball is returning to O. It still has positive displacement since its current position is still on the right of O. However, its velocity is negative since its positive displacement is decreasing and the direction of the velocity vector points left, which is the negative side.
By now you should be able to come up with a scenario where the ball has negative displacement and positive velocity.
You can observe the same phenomenon in daily life. Say, as a stretched spring bounces to its starting position, if we let the returning direction be positive, the string has negative displacement since it is on the negative direction, but has positive velocity. Bungee jump can also used to illustrate the phenomenon.
Answer:
Explanation:
Bundle's initial vertical velocity is zero because the plane is moving horizontally and its vertical component is zero. 0km/hr
Bundle's initial and uniform horizontal velocity is 350 km/hr .
The Bundle will maintain its horizontal velocity all along its journey until it hits the ground. It is so because it faces no force opposite to it. The only force that is acting on it is vertical gravitational force which increases its velocity vertically and not horizontally. So the horizontal component of its velocity just before hitting the ground is 350 km/hr.
If the horizontal velocity of plane is increased to 450 km/hr . there will be no effect on time of fall of the bundle because horizontal velocity has nothing to do with vertical displacement. vertical displacement is due to gravitational acceleration g. So time of fall will be the same.
If the earth stops rotating then the value of 'g'at equator will increase because when the earth rotates the gravity at every point remains uniform and when it stops rotating, the gravity increases as pressure is exerted on only one point at the equator.
The answer is b meteoroid