Answer:
9.62 μm
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 31.2 THz
Wavelength (λ) =..?
Next, we shall convert 31.2 THz to Hz.
This can be obtained as follow:
Recall:
1 THz = 1×10¹² Hz
Therefore,
31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz
31.2 THz = 3.12×10¹³ Hz
Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.
Finally, we shall determine the wavelength (λ) infrared radiation as follow:
Frequency (f) = 3.12×10¹³ Hz.
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =..?
V = λf
3×10⁸ = λ × 3.12×10¹³
Divide both side by 3.12×10¹³
λ = 3×10⁸ / 3.12×10¹³
λ = 9.62×10¯⁶ m
Converting 9.62×10¯⁶ m to micro metre (μm) we have:
1 m = 1×10⁶ μm
Therefore,
9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m
9.62×10¯⁶ m = 9.62 μm
Therefore, the wavelength of the infrared radiation is 9.62 μm
Answer:
Weak; a lot of potential energy.
Explanation:
Atoms contains small, negatively charged particles. His experiment showed that an atom contains negatively charged particles which was later known as electrons. This was confirmed by the Cathode Ray Experiment he conducted.
Answer:
th mol
Explanation:
When you balance an equation, you can refer back to the coefficients when calcuating mol and molar mass from the given information about one reactant to antoher reactant ot product. you use the coeffiecients for mol-mol ratio.
for example. if you are given A +3 B -----> 6C + 5D, and you have 10 mol of A and you have to find how many mols of C with 10 mol of A. then you would ratio it as A: C = 10A: 10C= 10(1): 10(6)= 10:60. so with 10 mol A you can make 60 mol C.
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