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4 years ago

Can someone help me today!? ASAP!!! Only number 5I need the answer today!!!!!!

Physics

2 answers:

Phantasy [73]4 years ago

7 0

The moths that did not evolve,due to the lack of traits to survive, died off. Over time the species evolved/adjusted to the new conditions. Soon enough the whole species had evolved.
Close enough? I had this in 7th grade. Good luck!

KengaRu [80]4 years ago

7 0

They did not survive because there would be no where for them to live so they would die off or the only way that they would survive is if they flew to another area that had the bark that they need

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The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t

Lubov Fominskaja [6]

Answer:

The distance from the radio station is 0.28 light years away.

Solution:

As per the question:

Distance, d = 4 ly

Frequency of the radio station, f = 854 kHz = $854\times 10^{3}\ Hz$

Power, P = 50 kW = $50\times 10^{3}\ W$

$I_{p} = 1\ photon/s/m^{2}$

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

$n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s$

Area of the sphere, A = $4\pi r^{2}$

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is $1\ photon/s/m^{2}$

$I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}$

$1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}$

$r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m$

Now,

We know that:

1 ly = $9.4607\times 10^{15}\ m$

Thus

$r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly$

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3 years ago

Make a 29 day timeline. Along the timeline draw and label the phases of the Moon starting with a full moon, crescent, first quar

Yanka [14]

Ummm.... this is a type of question that u have to do by yourself for class. Good luck ;)!!!!! Plz mark as brainliest

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3 years ago

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4 years ago

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Answer:

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Explanation:

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3 years ago

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