Two identical loudspeakers are some distance apart. A person stands 5.80 m from one speaker and 3.90 m from the other. What is t he fourth lowest frequency at which destructive interference will occur at this point? The speed of sound in air is 343 m/s.
1 answer:
Answer:
f = 632 Hz
Explanation:
As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength
here we know that
given that path difference from two loud speakers is given as
now we know that it will have fourth lowest frequency at which destructive interference will occurs
so here we have
now for frequency we know that
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