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hoa [83]
3 years ago
9

What is tan(16°)? A. 0.96 B.0.16 C.0.39 D.0.29

Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

D. 0.29

Explanation:

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tia_tia [17]

The amount of electrical energy used by the television is given by:

E=Pt

where P is the power of the device and t is the time.


The power of the television is P=315 W, while the total time is

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If we substitute these numbers into the formula, we find the energy:

E=Pt=(315 W)(1800 s)=5.67 \cdot 10^5 J


so, the correct answer is

(1) 5.67 × 10^5 J

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<span>When Kevin pulls his cotton shirt off his body, the electrons get transferred from the shirt (in form of static charges i.e. electrons to the body. So, the shirt becomes positively charged and Kevin’s body becomes negatively charged.

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How far will a rubber ball fall on 20 seconds?
Shtirlitz [24]

Given that:

time (t) = 20 s ,

        S = ?

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7 0
4 years ago
Hii I need help ASAP with this physics question
Readme [11.4K]

Between the top of the first and the top of the second loop, the coaster has lost potential energy = mgh, where h = 22.2 - 15 = 7.2m

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4 0
3 years ago
A wheel of diameter 40.0 cm starts from rest and rotates with a constant angular acceleration of 3.00 rad/s^2. At the instant th
xxMikexx [17]

Answer:

ac= 15.07 m/s²

Explanation:

The Wheel rotates with a constant angular acceleration.:

Centripetal acceleration is calculated as follows:

ac =ω² *R   Formula (1)

ac =v² / R    Formula (2)

Kinematics of the wheel

We apply the equations of circular motion uniformly accelerated :

ωf²= ω₀² + 2αθ  Formula (3)

v = ω* R Formula (4)

Where:

θ : angle that the wheel has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed   ( rad/s)

v: tangential velocity of a point on the rim ( m/s)

R : radius of  wheel (m)

ac: centripetal acceleration, (m/s²)

Data:

D = 40.0 cm : diameter of the wheel

R = D/2= 40.0 cm/ 2 = 20 cm = 0.2m

α = 3.00 rad/s^2

ω₀ = 0

n = 2 revolutions : number of revolutions

θ =2πn (rad) = 2π*2 (rad) = 4π rad

Calculate of the ωf

We replace data in the formula (3)

ωf²= ω₀² + 2αθ

ωf²= 0 + 2(3)(4π)

ωf²= 24π

w_{f} = \sqrt{24\pi }

ωf = 8.68 rad/s

Calculate of the v

We replace data in the formula (4)

v = ω*R

v = (8.68)*(0.2)

v = 1.736 m/s

Calculate of the ac

We replace data in the formula (1)

ac = ( ω)²*(R)

ac = (8.68)²*(0.2)

ac = 15.07  m/s²

We replace data in the formula (2)

ac = v²/ R

ac = ( 1.736  )²/(0.2)

ac = 15.07  m/s²

7 0
4 years ago
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