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Anit [1.1K]
3 years ago
11

A rectangle flower garden has a length that is 7 feet less than twice it's width. A 5-ft brick border is added around the garden

, and the area of the garden and the brick border is a total of 195 square ft. Find the dimensions of the garden without the brick border. L=? W=?
Mathematics
1 answer:
Delvig [45]3 years ago
7 0
Ok so if we call the width x then the length is 2x-7
Now by adding a 5 foot brick border around the edge the new dimensions are:
x+10 and 2x+3
Now we can form an equation to solve:
(x+10)(2x+3)=195
2x²+23x+30=195
2x²+23x-165=0
Now we can solve this for x
(2x+33)(x-5)=0
So x=-33/2 or x=5
As x cannot be less than 0 x must be equal to 5
So the dimensions of the garden are 5 feet by 3 feet
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Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

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