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2 years ago

Question 9 of 10 Which of the following is a scalar quantity? O

Physics

2 answers:

vekshin12 years ago

5 0

Answer:

work is scalar qualit y

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Reil [10]2 years ago

3 0

Answer:

(D) is the scalar quantity because unlike the other choices, no direction is attached to its magnitude.

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A space shuttle sits on the launch pad for 2.0 minutes, and then goes from rest to 4600 m/s in 8.0 minutes. Treat its motion as

SpyIntel [72]

Answer:

a.) a = 0 ms⁻²

b.) a = 9.58 ms⁻²

c.) a = 7.67 ms⁻²

Explanation:

a.)

Acceleration (a) is defined as the time rate of change of velocity

$a = \frac{v_{2} - v_{1} } {t}$

Given data

Final velocity = v₂ = 0 m/s

Initial velocity = v ₁ = 0 m/s

As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,

a = 0 ms⁻²

b.)

Given data

As the space shuttle start from rest, So initial velocity is zero

Initial velocity = v₁ = 0 ms⁻¹

Final velocity = v₂ = 4600 ms⁻¹

Time = t = 8 min = 480 s

By the definition of Acceleration (a)

$a = \frac{v_{2} - v_{1} } {t}$

$a = \frac{4600 - 0 } {480}$

a = 9.58 ms⁻²

c.)

Given data

As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero

Initial velocity = v₁ = 0 ms⁻¹

Final velocity = v₂ = 4600 ms⁻¹

Time = t = 10 min = 600 s

By the definition of Acceleration (a)

$a = \frac{v_{2} - v_{1} } {t}$

$a = \frac{4600 - 0 } {600}$

a = 7.67 ms⁻²

8 0

3 years ago

How long a star lives and what it becomes at the end of its life depends primarly on what

liraira [26]

I believe the answer would be mass. Low mass stars and medium mass stars often become white dwarfs when they die while high mass stars explode in violent explosions called supernovas and usually leave behind a black hole or a neutron star.

4 0

3 years ago

You launch a ball at an angle of 35 degrees above the horizontal with an initial velocity of 38 m/s. What is the time the ball w

gayaneshka [121]

Vf=Vi+at

0=38+(-9.8)(?)

?=38-0+(-9.8)

?=28.2 s

5 0

2 years ago

A metal bar moves through a magnetic field. the induced charges on the bar are

Dmitry [639]

I would say its a positive cgarge

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3 years ago

A ray of light traveling through air strikes a piece of diamond at an angle of incidence equal to 56 degrees. Calculate the angu

Montano1993 [528]

Answer:

The angle of separation is $\Delta \theta = 0.93 ^o$

Explanation:

From the question we are told that

The angle of incidence is $\theta _ i = 56^o$

The refractive index of violet light in diamond is $n_v = 2.46$

The refractive index of red light in diamond is $n_r = 2.41$

The wavelength of violet light is $\lambda _v = 400nm = 400*10^{-9}m$

The wavelength of red light is $\lambda _r = 700nm = 700*10^{-9}m$

Snell's Law can be represented mathematically as

$\frac{sin \theta_i}{sin \theta_r} = n$

Where $\theta_r$ is the angle of refraction

=> $sin \theta_r = \frac{sin \theta_i}{n}$

Now considering violet light

$sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}$

substituting values

$sin \theta_r__{v}} = \frac{sin (56)}{2.46}$

$sin \theta_r__{v}} = 0.337$

$\theta_r__{v}} = sin ^{-1} (0.337)$

$\theta_r__{v}} = 19.69^o$

Now considering red light

$sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}$

substituting values

$sin \theta_r__{R}} = \frac{sin (56)}{2.41}$

$sin \theta_r__{R}} = 0.344$

$\theta_r__{R}} = sin ^{-1} (0.344)$

$\theta_r__{R}} = 20.12^o$

The angle of separation between the red light and the violet light is mathematically evaluated as

$\Delta \theta = \theta_r__{R}} - \theta_r__{V}}$

substituting values

$\Delta \theta =20.12 - 19.69$

$\Delta \theta = 0.93 ^o$

6 0

3 years ago