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mrs_skeptik [129]
3 years ago
15

The final step in a descriptive investigation is to _____. A. see if your data support the hypothesis B. make your observations

and record them C. revise your procedure and start over again D. decide what information should be collected
Chemistry
2 answers:
Katen [24]3 years ago
8 0

A. see if your data support the hypothesis

Explanation:

The final step in a descriptive investigation is to see if your data supports the hypothesis. Like any other experiment, the hypothesis are usually tested when investigation studies are carried out.

  • Descriptive investigation employs the use of logic, creative and critical thinking.
  • Most times, notes are usually take following a well laid investigation plan and outline.
  • After different sources have been consulted and the study is drawn to a close the data and finding are analyzed to see how they compare to the hypothesis.

learn more:

Deductive reasoning brainly.com/question/5003338

#learnwithBrainly

Naddika [18.5K]3 years ago
4 0

Answer:

a have a good day

Explanation:

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Calculate the density for a rectangular block using the following measurements: Length = 10 cm, Width = 1.1 cm, Height = 15 cm,
Ksivusya [100]

Answer:

0.40 g/cm3

Explanation:

density = mass / volume.

mass = 65.2 grams

volume = 10*1.1*15=165 cm3

so density = 65.2/165=0.40 g/cm3

3 0
3 years ago
8th grade Science Help<br><br> Please Don't go off what i said
julia-pushkina [17]
Actually your answer is correct. Your answer that you picked is correct because the basic SI unit for mass is a kilograms, so therefore your answer is 13kg which you picked.
3 0
3 years ago
What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?
sashaice [31]

Answer:

\boxed {\boxed {\sf PCl_3}}

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

  • 22.5 g P
  • 77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

  • P: 30.974 g/mol
  • Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. 22.5 \ g \ P  * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P

77.5 \ g \ Cl  * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl

Divide both of the moles by the smallest number of moles to find the mole ratio.

\frac {0.7264157035} {0.7264157035} = 1

\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>

4 0
3 years ago
How many mol of butan-1-ol are in 10.0 mL of butan-1-ol?
ELEN [110]

Answer:

2) 0.109 mol

Explanation:

The density of butan-1-ol is 0.8098g/mL. And its molar mass is: 74.121g/mol.

First, we need to convert volume of butan-1-ol to mass:

10.0mL * (0.8098g / mL) = 8.098g of butan-1-ol

Now, we need to convert these grams to moles using molar mass:

8.098g * (1mol / 74.121g) = 0.109 moles of butan-1-ol

Right answer is:

<h3>2) 0.109 mol </h3>

7 0
3 years ago
How does a temperature increase cause the rate of a reaction to increase?
AVprozaik [17]

Answer:

the answer is c because it will have a equilibrium constant for the action

4 0
3 years ago
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