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victus00 [196]
3 years ago
12

The camel stores the fat tristearin (C57H110O6) in its hump. As well as being a source of energy, the fat is also a source of wa

ter because, when it is used, the reaction 2 C57H110O6(g) + 163 O2(g) 114 CO2(g) + 110 H2O(ℓ) takes place. What mass of water is available from 2.2 pound of this fat? Answer in units of g.
Chemistry
1 answer:
Aneli [31]3 years ago
8 0

Answer:

1109 g H₂O

Explanation:

2.2 pounds can be converted to grams using a conversion ratio:

(2.2lb)(453.592g/lb) = 997.9024 g C₅₇H₁₁₀O₆

The mass in grams is converted to moles using the molecular weight of tristearin (891.48 g/mol)

(997.9024 g)(mol/891.48g) = 1.119...mol C₅₇H₁₁₀O₆

The moles of C₅₇H₁₁₀O₆ can be related to the moles of water through the molar ratio:

(1.119mol C₅₇H₁₁₀O₆)(110 H₂O/2 C₅₇H₁₁₀O₆) = 61.545 mol H₂O

The mass of water is then calculated using the molecular weight (18.02 g/mol):

(61.545 mol)(18.02 g/mol) = 1109 g H₂O

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Which of the following bases are strong enough to deprotonate CH3CH2CH2C≡CH (pKa = 25), so that equilibrium favors the products?
seraphim [82]

Answer:

a, and f.

Explanation:

To be deprotonated, the conjugate acid of the base must be weaker than the acid that will react, because the reactions favor the formation of the weakest acid. The pKa value measures the strength of the acid. As higher is the pKa value, as weak is the acid. So, let's identify the conjugate acid and their pKas:

a. NaNH2 will dissociate, and NH2 will gain the proton and forms NH3 as conjugate acid. pKa = 38.0, so it happens.

b. NaOH will dissociate, and OH will gain the proton and forms H2O as conjugate acid. pKa = 14.0, so it doesn't happen.

c. NaC≡N will dissociate, and CN will gain a proton and forms HCN as conjugate acid. pKa = 9.40, so it doesn't happen.

d. NaCH2(CO)N(CH3)2 will dissociate and forms CH3(CO)N(CH3)2 as conjugate acid. pKa = -0.19, so it doesn't happen.

e. H2O must gain one proton and forms H3O+. pKa = -1.7, so it doesn't happen.

f. CH3CH2Li will dissociate, and the acid will be CH3CH3. pKa = 50, so it happens.

6 0
3 years ago
I have to circle the one that fits correctly
nadya68 [22]
The answer is chloroplast
8 0
2 years ago
Read 2 more answers
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
2 years ago
Read the information about the halogen family.
Elodia [21]

Answer:

See explanation

Explanation:

Chlorine is a member of the halogen family known as a toxic yellowish green gas. Inhalation of chlorine for a prolonged period of time leads to  pulmonary edema. If a person comes in contact with compressed liquid chlorine the person may experience frostbite of the skin and eyes.

However chlorine is very useful in water disinfection and is preferred in water treatment because it provides residual disinfection of the treated water.

Chlorine gas may be dissolved in NaOH to form oxochlorate I which is used as a bleach in cleaning.

7 0
3 years ago
Determine the molarity of 56.00 grams of aluminum nitrate in 450 milliliters of solution?
SVETLANKA909090 [29]

Answer:

4.62 M

Explanation:

Molarity = moles/volumes (L), so you need to find the moles and the volumes in liters.

Finding the volume is easy because you just have to convert mL to L, so the volume is 0.45 L

Next, find the moles. You can do this by using the molar mass of aluminum to convert the grams to moles. The molar mass of aluminum is 26.98 g/mol.

56 g * (1 mol/26.98 g) = 2.08 mol

Now, divide the moles (2.08) by the volume (.45 L)

Molarity = 4.62 M

3 0
3 years ago
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