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AlladinOne [14]
2 years ago
12

As a bond netween a hydrohen atom and sulfur atom is formed, electrons are

Chemistry
1 answer:
aleksley [76]2 years ago
7 0

shared to form an ionic bond.


I hope this helps!

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n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?
victus00 [196]

Answer:

The coefficient that should be inserted in front of chlorine is 2

Explanation:

Sn  +  2Cl₂   →  SnCl₄

As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.

Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.

The law of conservation of mass must be respected in every chemical equation

4 0
3 years ago
What is the percent composition by mass of oxygen in ca(no3)2 (gram-formula mass = 164 g/mol)?a.9.8%b.29%c.48%d.59%?
Mila [183]
Percent composition by mass of oxygen =
((16.0*6)/(40.1+2*(14.0+16.0*3)))*100%
= 58.5%
therefore, the answer is D
8 0
3 years ago
Read 2 more answers
EASYYYYYYY!!!!!!!!!!!!!!
eduard

Answer:

Agriculture was practiced for thousands of years without the use of artificial chemicals. Artificial fertilizers were first created during the mid-19th century. These new agricultural techniques, while beneficial in the short term, had an Institute of Plant Industry to improve traditional farming methods in India.

Explanation:

6 0
2 years ago
Brenda rode a skateboard 95 meters west. It took her 20 seconds. What was
Artemon [7]

Answer:

D. 4.75 m/s west

Explanation:

You can immediately get the answer once you know the formula for<em> velocity.</em>

  • The formula for velocity is: Velocity (V) = \frac{distance (d)}{time (t)}

The distance is 95 meters while the time is 20 seconds. All you have to do is to divide <u>95 meters by 20 seconds</u>.

Let's solve:

  • V = \frac{d}{t}
  • V = \frac{95 meters}{20 seconds}
  • V = 4.75 meters per second

Since Brenda is going west with her her skateboard, then you have to add <em>west </em>as her direction.

Brenda's velocity is 4.75 m/s west.

5 0
3 years ago
What mass of butane in grams is necessary to produce 1.5×103 kJ1.5×103 kJ of heat? What mass of CO2CO2 is produced? Assume the r
saul85 [17]

32.8 g of Butane is required and 99.3 g of CO₂ is produced

<u>Explanation:</u>

The above mentioned reaction can be written as,

C₄H₁₀(g) + 13 O₂(g) → 4CO₂(g) + 5 H₂O(g)     where ΔH (rxn)= -2658 kJ

It is given that 1.5 × 10³ kJ of energy is produced, the original reaction says that 2658 kJ of heat is produced, which means that less than one mole of butane is used in the reaction.

That is

$\frac{1500}{2658}=0.564 \text { moles }    of butane reacted

Now this moles is converted into mass by multiplying it with its molar mass  = 0.564 mol × 58.122 g / mol

                     = 32.8 g of butane.

Mass of CO₂ produced = 0.564 ×44.01 g /mol × 4 mol

                                        = 99.3 g of CO₂

Thus 32.8 g of Butane is required and 99.3 g of CO₂ is produced

7 0
3 years ago
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