<h2>
Answer: 10615 nm</h2>
Explanation:
This problem can be solved by the Wien's displacement law, which relates the wavelength 
where the intensity of the radiation is maximum (also called peak wavelength) with the temperature 
of the black body.
In other words:
<em>There is an inverse relationship between the wavelength at which the emission peak of a blackbody occurs and its temperature.</em>
Being this expresed as:
(1)
Where:
is in Kelvin (K)
is the <u>wavelength of the emission peak</u> in meters (m).
is the <u>Wien constant</u>, whose value is 
From this we can deduce that the higher the black body temperature, the shorter the maximum wavelength of emission will be.
Now, let's apply equation (1), finding :
(2)
Finally:
This is the peak wavelength for radiation from ice at 273 K, and corresponds to the<u> infrared.</u>
Answer:
(a) whether slipping occurs between the belt and the cylinder i think is the answer dont hate if you get it wrong please and thank you.
Explanation:
i am just guessing otay.
Option B
Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury correctly describes the usual order of planets inward toward the sun
<u>Explanation:</u>
Our solar system continues much considerably than the eight planets that revolve around the Sun. The position of the planets in the solar system, commencing inward to the sun is the accompanying: Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury.
Most next to the Sun, simply rocky material could resist the heat. For this logic, the first four planets: Mercury, Venus, Earth, and Mars are terrestrial planets. The four large outer worlds — Jupiter, Saturn, Uranus, and Neptune: because of their enormous size corresponding to the terrestrial planets. They're also frequently composed of gases like hydrogen, helium, and ammonia preferably than of rocky surfaces.
Answer:
u=36.8m/s
Explanation:
because of the acceleration is a constant acceleration we can use one of the "SUVAT" equations
u^2=v^2-2ā*s. where:
u^2 stands for intial velocity
v^2 stands for final velocity
since the cougar skidded to a complete stop the final velocity is zero.
u^2=v^2-2ā*s
u^2=(0)^2 -2(-2.87 m/s^2)*236 m
u^2=0+5.74m/s^2* 236m
u^2=1354.64m^2/s^2
u=√1354.64m^2/s^2
u=36.8m/s (approximate value)
when ever the acceleration is constant you can use one of the following equation to find the required value.
1. v = u + at. (no s)
2. s= 1/2(u+v)t. (no ā)
3. s=ut + 1/2at^2. ( no v)
4. v^2=u^2 + 2āS. (no t). 5. s= vt - 1/2at^2. (no u)
Answer:
Explanation:
Y = 5 Sin27( .2x-3t)
= 5 Sin(5.4x - 81 t )
Amplitude = 5 m
Angular frequency ω = 81
frequency = ω / 2π
= 81 / (2 x 3.14 )
=12.89
Wave length λ = 2π / k ,
k = 5.4
λ = 2π / 5.4
= 1.163 m
Phase velocity =ω / k
= 81 / 5.4
15 m / s.
The wave is travelling in + ve x - direction.
