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coldgirl [10]
3 years ago
11

An ideal gas trapped inside a thermally isolated cylinder expands slowly by pushing back against a piston. The temperature of th

e gas
a. decreases.
b. increases.
c. remains the same if the process occurs quickly.
d.remains the same.
e. increases if the process occurs quickly.
Physics
1 answer:
Archy [21]3 years ago
3 0

Answer:

Explanation:idk sry

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What type of cooling would a scientist determine formed an igneous rock found with large crystals? Slow cooling Medium rate cool
Dmitriy789 [7]

Slower cooling engenders the growth of larger crystals in igneous rocks, thus, your answer should be slow cooling!

Hope this helped!

5 0
2 years ago
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What information should be posted on or near a dishwasher?
Murljashka [212]
A.. in case of any problems that may occur you would know what company to call
7 0
3 years ago
In a liquid with a density of 1400 kg/m3 , longitudinal waves with a frequency of 370 Hz are found to have a wavelength of 8.40
VARVARA [1.3K]

Answer:

Bulk modulus = 1.35 × 10^{10} Pa

Explanation:

given data

density = 1400 kg/m³

frequency = 370 Hz

wavelength = 8.40 m

solution

we get here bulk modulus of the liquid that is

we know Bulk Modulus = v^2*\rho   ...............

here \rho is density i.e 1400 kg/m³

and v is =  frequency × wavelength

v = 370 × 8.40 = 3108 m/s

so here bulk modulus will be as

Bulk modulus = 3108² × 1400

Bulk modulus = 1.35 × 10^{10} Pa

3 0
3 years ago
A hybrid is
Sophie [7]
The correct answer is heterozygous.
7 0
3 years ago
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A disk-shaped merry-go-round of radius 2.63 m and mass 152 kg rotates freely with an angular speed of 0.526 rev/s. A 51.7 kg per
zalisa [80]

 Explanation:

Given

radiusr=2.63 m

N=0.526 rev/s

\omega =3.30 rad/s

mass disc  M=152 kg

mass of person  m=51.7 kg

velocity of Person  v=2.76 m/s

moment of inertia  I=Mr^2

I=0.5\times 152\times 2.63^2=827.64 kg-m^2

Initial angular momentum

L_i=I\omega +mvr

L_i=827.64\times 3.30+51.7\times 2.76\times 2.63

L_i=2731.212+375.27=3106.48 Js

Final Moment inertia

I_f=0.5Mr^2+mr^2

I_f=(152\cdot 0.5+51.7)\cdot (2.63)^2=1185.243 kg-m^2

final angular momentum

L_f=I_f\omega _f

Conserving angular momentum

L_i=L_f

3106.48=1408.97\times \omega _f

\omega _f=2.62 rad/s

4 0
2 years ago
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