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3 years ago

What does the 3 indicate in 1s22s22p63s1

Chemistry

2 answers:

olchik [2.2K]3 years ago

6 0

I think the 3 indicates the number of molecules

gladu [14]3 years ago

6 0

The last shell has 3 electrons I think

You might be interested in

What is a double displacement reaction?

nexus9112 [7]

<h2>Double displacement reaction:</h2>

A double displacement reaction is a type of chemical reaction where two compounds react, and positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

<h3>For example:</h3>

Na2S+2HCl→2NaCl+H2S

hope it's helpful :)

4 0

3 years ago

Which statement about the gas laws is correct?

Elena-2011 [213]

Answer:

Gay-Lussac's law states that pressure and temperature are directly proportional

Explanation:

Gay-Lussac's law states that pressure and temperature are directly proportional. This always occurs if the volume keeps in constant.

n and V are not directly proportional, they are the same.

At Charles Gay Lussac's law

V1 = V2

n1 = n2

T1 < T2

P1 < P2

P1 / T1 = P2 / T2

If the pressure is contant:

V1 / T1 = V2 /T2

4 0

3 years ago

Some fats are called "saturated" fats because __________. Select one: a. their carbon skeleton is bent to form four fused rings

marin [14]

Answer:

All carbons in the carbon skeleton contain the maximum number of hydrogen atoms

Explanation:

Saturated fats are class of compounds having all the fatty acids containing only single bonds. In other words, carbon skeleton has only single bonds.

Unsaturated compounds undergoes hydrogenation to form saturated fats.

In hydrogenation, hydrogen atoms are added to the carbon attached to double bond. After become saturated, no more hydrogen atoms can be added.

Therefore, it can be said that in saturated fats all carbons in the carbon skeleton contain the maximum number of hydrogen atoms.

6 0

3 years ago

When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h

Pavel [41]

NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃ <span>+ 3O</span>₂ ⇒<span> 2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol : 3mol : 2mol
0.133mol : 0.116mol : 0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>

6 0

4 years ago

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

$Q_1=-Q_2$

Mass of steel= $m_1$

Specific heat capacity of steel = $c_1=0.452 J/g^oC$

Initial temperature of the steel = $T_1=2.00^oC$

Final temperature of the steel = $T_2=T=21.50^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2= 105 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=22.00^oC$

Final temperature of water = $T_2=T=21.50^oC$

$Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))$

On substituting all values:

$(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}$

<h3>25.0 grams is the mass of the steel bar.</h3>

3 0

4 years ago

Read 2 more answers