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o-na [289]
3 years ago
7

An agent has just listed a power plant. This is an example of what type of real estate?

Physics
1 answer:
klio [65]3 years ago
6 0

Answer: industrial properties

Explanation:

The power plant listed by the agent falls under industrial property. An industria property is a property which is either used in manufacturing, rentage, warehousing, processing e.t.c.

in this case the plant Would be used in the generation of power which would be sold. so yes the property falls under the category

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A 6157 N piano is to be pushed up a(n) 2.41 m frictionless plank that makes an angle of 21.9 ◦ with the horizontal. Calculate th
xz_007 [3.2K]

Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

W=Fd\ sin\theta

Since, F=F\ sin\theta (in vertical direction)

W=6157\times 2.41\ sin(21.9)

W = 5534.53 J

So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

3 0
4 years ago
It is easier to roll a stone up a sloping road than to lift it vertical upwards because.
kvasek [131]

Answer:

Because the force one needs to apply is reduced.

Explanation:

  • Work can be expressed in terms of force and distance as follows,

                        Work = Force × distance

  • To be more precise, the selection of these two parameters should be in a manner that the distance is what the line of action of the force traces.
  • It is obvious that for a given amount of work when one parameter is changed the other changes to counteract the change of the first one.
  • Imagine the situation shown in the attached figure. The amount of work that needs to be done during the lifting of the mass to a height of \small h vertically is E = mg\times h = mgh.
  • On the slope, however, one needs to push the object an L distance up to get the object to that h height ultimately.
  • The work he does on the slope is mgh = F\times L and sinceL > h , F < mg.
  • The force that needs to be applied is less than that applied in the vertical lift. Hence it feels easier.             #SPJ4                                                                    

3 0
1 year ago
Which statement is the best example of pseudoscience?
Nady [450]
<span>pseudoscience includes beliefs theories, or practices that have been or are considered scientific, but have no basis in scientific fact.
This could mean the were disproved scientifically, can't be tested or lack evidence to support them.
Examples:Channeling- involves communicating with a spirit through a person

 Astrology- beliefs that humans are affected by the position of celestial bodies
</span>
5 0
3 years ago
Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another. The cubes are lined up
Westkost [7]

Answer:

24 N

Explanation:

m = mass of the cube = 6.0 kg

Consider the three cubes together as one.

M = mass of the three cubes together = 3 m = 3 (6.0) = 18 kg

a = acceleration of the combination = 2 ms⁻²

F = Force applied on the combination

Using Newton's second law

F = ma = (18) (2) = 36 N

F_{L} = Force by the left cube on the middle cube

Consider the forces acting on left cube, from the force diagram, we have

F - F_{L} = ma \\36 - F_{L} = (6) (2)\\F_{L} = 24 N

4 0
3 years ago
Two blocks of masses m and M are connected by a string and pass over a frictionless pulley. Mass m hangs vertically, and mass M
horsena [70]

Answer:

sin\theta - \mu_k cos\theta = \frac{m}{M}

sin\theta - \mu_k cos\theta = 1

Explanation:

Force of friction on M mass so that it will move down the inclined plane is given as

F_f = \mu Mgcos\theta

now if it is moving down the inclined plane at constant speed

so we will have

Mgsin\theta - T - \mu mgcos\theta = 0

on other side the mass "m" will go up at constant speed

so we have

T - mg = 0

so we have

Mgsin\theta = \mu Mgcos\theta + mg

so we have

sin\theta - \mu_k cos\theta = \frac{m}{M}

for special case when m = M

then we have

sin\theta - \mu_k cos\theta = 1

5 0
3 years ago
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