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mash [69]
3 years ago
8

What are factors that would impede positive parenting and family relationships?

Physics
2 answers:
Oduvanchick [21]3 years ago
5 0

Answer:

Factors that would impede positive parenting and family relationships are discussed below.

Explanation:

Various factors would impede positive parenting and family relationships such as

  • Jealousy is the major cause of impede family relationship and lead to unhealthy family relationship.
  • Acting controlling and extra possessiveness lead to unhealthy family relationship and develops doubt for each other in a family and also the same in the case of positive parenting.
  • The day to day lifestyle in which no give time to each other in the family leads to unhealthy family relationships and exactly the same in parenting also.

fomenos3 years ago
4 0
•respect •love •comunication •understanding that's it hope this answer ur question
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In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.


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The relative velocity is the velocity that the body A would appear to an observer on the body B and vice versa.


In this case the relative velocity would be arrived by summing up our velocity with the velocity of the ship as the object (I) is travelling in the ship.


Relative velocity = Velocity of Body A+ Velocity of Body B.


Velocity of the ship traveling towards the north with respect to land(A)= 13.0m/s. (Given)

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3 years ago
What is an example of a negative incentive for producers
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3 years ago
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Answer:

214.9 \Omega

Explanation:

The three resistors are connected in parallel: this means that the potential difference across each resistor is the same as the voltage of the battery. This can be calculated using the information about the 38.7 \Omega resistor: in fact, since we know its resistance and the current flowing through it (0.155 A), we can find the potential difference across this resistor, which is equal to the voltage of the battery:

V=IR=(0.155 A)(38.7 \Omega)=6.0 V

We also know the total current in the circuit, 0.250 A. This means that we can find the total resistance of the circuit, using Ohm's law:

R_{eq}=\frac{V}{I}=\frac{6.0 V}{0.250 A}=24 \Omega

So now we now the total resistance and the resistance of two of the 3 resistors; therefore, we can find the resistance of the 3rd resistor:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\frac{1}{R_3}=\frac{1}{R_{eq}}-\frac{1}{R_1}-\frac{1}{R_2}=\frac{1}{24 \Omega}-\frac{1}{38.7\Omega}-\frac{1}{89.5\Omega}=0.00465 \Omega^{-1}\\R_3=\frac{1}{0.00465 \Omega^{-1}}=214.9 \Omega

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