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Ne4ueva [31]
3 years ago
11

What is it called after data is collected they are often arranged in a what?

Physics
2 answers:
Sveta_85 [38]3 years ago
8 0
Arranged in a chart or displayed in a graph...Pretty vague question...
valentinak56 [21]3 years ago
3 0
They are often arranged in a category 
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A strong lightning bolt transfers an electric charge of about 31 C to Earth (or vice versa). How many electrons are transferred?
olchik [2.2K]

Answer:

m=5.78\times 10^{-3}\ g

n_e=1.935\times 10^{20} is the no. of electrons

Explanation:

Given:

  • quantity of charge transferred, Q=31\ C

<u>No. of electrons in the given amount of charge:</u>

As we have charge on one electron 1.602\times 10^{-19}\ C

so,

n_e=\frac{Q}{e}

n_e=\frac{31}{1.602\times 10^{-19}}

n_e=1.935\times 10^{20} is the no. of electrons

  • Now if each water molecules donates one electron:

Then we require n=1.935\times 10^{20} molecules.

<u>Now the no. of moles in this many molecules:</u>

n_m=\frac{n}{N_A}

where

N_A=6.022\times 10^{23} Avogadro No.

n_m=\frac{1.935\times 10^{20}}{6.022\times 10^{23}}

n_m=3.213\times 10^{-4}\ moles

  • We have molecular mass of water as M=18 g/mol.

<u>So, the mass of water in the obtained moles:</u>

n_m=\frac{m}{M}

where:

m = mass in gram

3.213\times 10^{-4}=\frac{m}{18}

m=5.78\times 10^{-3}\ g

7 0
3 years ago
The latent heat of fusion of alcohol is 50 kcal/kg and its melting point is -54oC. It has a specific heat of 0.60 in its liquid
sashaice [31]

Answer:

C

Explanation:

To melt the alcohol

Heat needed = M . L  = 2 . 25  = 50 kcal

To warm up the alcohol

Heat needed = M . sp. ht. . ∆t   = 2 . 0.6 . 100  = 120 kcal

Total heat needed = 170 kcal

Assuming that 0.6 kcal/ kg / ˚C  is the specific heat and that the answer is wanted in kcal ( a rather odd unit to be in use here.)

5 0
3 years ago
A student standing in a canyon yells "echo", and her voice produces a sound wave of frequency of f = 0.61 kHz. The echo takes t
klasskru [66]

Answer:

d=627.9\ m  is the distance from the obstacle of reflection.

wavelength \lamb=0.5279\ m

Explanation:

Given that:

  • frequency of sound, f=610\ Hz
  • time taken for the echo to be heard, t=3.9\ s
  • speed of sound, v=322\ m.s^{-1}

We know,

\rm distance = speed \times time

<em>During an echo the sound travels the same distance back and forth.</em>

2d=v.t

2d=322\times 3.9

d=627.9\ m  is the distance from the obstacle of reflection.

<u>Now the wavelength of sound waves:</u>

\lambda=\frac{v}{f}

\lambda=\frac{322}{610}

\lamb=0.5279\ m

3 0
3 years ago
If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!
Hoochie [10]

Answer:

I can't see the post :/

Explanation:

5 0
3 years ago
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