Ask question

Ask question

All categories

2 years ago

8

A sphere moves in simple harmonic motion with a frequency of 4.40 Hz and an amplitude of 3.50 cm. (a) Through what total distanc

e (in cm) does the sphere move during one cycle of its motion

1 answer:

Anna [14]2 years ago

6 0

Answer:

It will move a distance of 4 * 3.5 = 4 cm in one cycle.

zero to max A, back to zero, zero to min A, back to zero (4 * A)

You might be interested in

PSYCHOLOGY! A _________ is a graphical representation of association between variables.

pshichka [43]

Answer:

A. Scatterplot

Explanation:

because it is

5 0

3 years ago

Read 2 more answers

Suppose a 2.0kg bird is flying at a speed of of 1m/s. It’s kinetic energy would be what?

Ganezh [65]

As we know that the formula of kinetic energy will be

$KE = \frac{1}{2} mv^2$

now here we know that

m = 2 kg

v = 1 m/s

so from the above equation we have

$KE = \frac{1}{2}(2)(1^2)$

$KE = 1 J$

7 0

3 years ago

A plane electromagnetic wave, with wavelength 5 m, travels in vacuum in the positive x direction with its electric vector E, of

Dafna1 [17]

Answer:

Explanation:

E₀ = 229.1 V/m

E = E₀ / √2 = 229.1 / 1.414 = 162 V/m

B = E / c ( c is velocity of em waves )

= 162 / (3 x 10⁸) = 54 x 10⁻⁸ T

rate of energy flow = ( E x B ) / μ₀

= 162 x 54 x 10⁻⁸ / 4π x 10⁻⁷

= 69.65 W per m².

5 0

3 years ago

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)$

so we have

$H = 1.47 m$

Part b)

Similarly when spring is compressed by 4 cm

then we have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)$

so we have

$H = 5.94 m$

8 0

3 years ago

Which of the following describe circumstances under which an exculpatory clause is generally unenforceable? Select all that appl

Sveta_85 [38]

Answer:

a. When the parties have unequal bargaining power

c. When it covers public transportation

Explanation:

Exculpatory clauses are often found in agreements between a company and a consumer when the activity is in danger, such as at a fitness center or ski resort. The company wants the consumer to understand the risk involved and to avoid lawsuits, so it includes a disclaimer in its contract. These clauses are used to limit liability, so they are not enforced when the parties have unequal bargaining power and when covering public transport.

6 0

3 years ago