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2 years ago

8

A sphere moves in simple harmonic motion with a frequency of 4.40 Hz and an amplitude of 3.50 cm. (a) Through what total distanc

e (in cm) does the sphere move during one cycle of its motion

1 answer:

Anna [14]2 years ago

6 0

Answer:

It will move a distance of 4 * 3.5 = 4 cm in one cycle.

zero to max A, back to zero, zero to min A, back to zero (4 * A)

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Lowest frequency?_______

Sergio039 [100]

Answer:

Radio waves are the lowest frequency

Explanation:

Here is the order of frequencies highest to lowest to help you in the future:

gamma rays

X-rays

ultraviolet radiation

visible light

infrared radiation

radio waves

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2 years ago

If you were on a decision making board with the task of choosing which innovation to fund, what criteria would you use to make y

faust18 [17]

Explanation:

The criteria for decision making would be

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3 years ago

Suppose the earth is shaped as a sphere with radius 4,0004,000 miles and suppose it rotates once every 24 hours. How many miles

Alenkinab [10]

Answer:

1047 miles

Explanation:

The radius of the Earth is

$r = 4000$ (miles)

So its circumference, which is the total length of the equator, is given by

$L=2\pi r= 2\pi(4000)=25133 mi$

Now we know that the Earth rotates once every 24 hours. So the distance through which the equator moves in one hour is equal to its total length divided by the number of hours, 24:

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8 0

3 years ago

Why is there an upward force on objects in water?

Paraphin [41]

If you'r referring to some objects, it means that the mass of the object is less than the water so it floats. If the mass of an object is greater than the mass of the water, it will sink. Compare it to a balloon, helium makes it rise, while normal air makes it sink.

4 0

3 years ago

n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us

barxatty [35]

Answer:

The answer is " $(1.265 \pm 0.010) \ s \ and \ 0.709 \%$ "

Explanation:

In point i:

$T_{theo}= 2\pi \sqrt{\frac{l}{g}}$

$=2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s$

If error in the theoretical time period :

$\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2} \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}$

$= 0.010 \ s$

$T_{theo} = (1.265 \pm 0.010) \ s$

In point ii:

$\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100$

<h3> $= \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%$ </h3>

5 0

3 years ago