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Ira Lisetskai [31]
3 years ago
12

What is oxygen an example of? a mixture, an element, a compound, or a solution

Physics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer: element

Explanation:

Couldn't be a compound because contains same type of atoms. Can't be a mixture either because not physically mixed or anything. Isn't a solution ofc because oxygen is a gas.

You might be interested in
How does gravity keep the moon in orbit around earth
lidiya [134]

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

3 0
3 years ago
Fast need answers <br>Find the amount of force if the body has pressure of 178 Pa on 18 mm²​
guajiro [1.7K]

Answer:

Force = 3.204Newton

Explanation:

Given the following data;

Pressure = 178

Area = 18 mm² to meter = 18/1000 = 0.018 m²

To find the force;

Force = pressure * area

Force = 178 * 0.018

Force = 3.204 Newton.

4 0
3 years ago
A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.
ohaa [14]

Answer:

speed of a particle  = 2.31 × 10^{6} m/s

energy of proton required = 27.77 KeV

energy of electron required =  15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and  energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB    ..............1

and force due to electric field E = qE   .....................2

so without deflection force due to magnetic field  = force due to electric field  

so here qvB = qE

and V = \frac{E}{B}    ...................3

put here value

V =  \frac{0.51*10^6}{0.22}

speed of a particle  = 2.31 × 10^{6} m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × \frac{V^2}{2}

put here value

energy of proton required = 1.67 × 10^{-27} × \frac{(2.31*10^6)^2}{2}

energy of proton required = 4.45 × 10^{-15} J

energy of proton required = 4.45 × 10^{-15} J ÷ (1.602 × 10^{-19}

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × \frac{V^2}{2}

put here value

energy of electron required = 9.11 × 10^{-31} × \frac{(2.31*10^6)^2}{2}

energy of electron required =  24.305× 10^{-19} J

energy of electron required =  24.305 × 10^{-19} J ÷ (1.602 × 10^{-19}  

energy of electron required =  15.171 eV

5 0
4 years ago
Read 2 more answers
1. Which of the following types of energy is
Sholpan [36]

Answer:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

5 0
2 years ago
A rock is projected from the edge of the top of a building with an initial velocity of 21.6 m/s at an angle of 37◦ above the hor
dusya [7]
<h2>Horizontal component of the rock’s velocity when it strikes the ground is 17.25 m/s</h2>

Explanation:

In horizontal direction there is no acceleration or deceleration for a rock projected at an initial angle of 37° off the ground.

So the horizontal component of velocity always remains the same.

Horizontal component of velocity is the cosine component of velocity.

Initial velocity, u = 21.6 m/s

Angle, θ = 37°

Horizontal component of velocity = u cosθ

Horizontal component of velocity = 21.6 cos37

Horizontal component of velocity = 17.25 m/s

Since the horizontal velocity is unaffected, we have

    Horizontal component of the rock’s velocity when it strikes the ground = 17.25 m/s

5 0
3 years ago
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