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Lady bird [3.3K]
2 years ago
9

What should a free-body diagram look like for a skydiver who has opened his parachute and is now slowing down as he falls?

Physics
2 answers:
iogann1982 [59]2 years ago
7 0

answer A is correct i took the test


Ksivusya [100]2 years ago
5 0

Answer:

There is an arrow up for air resistance and an arrow down for gravity. The arrow up is longer than the arrow down.

Explanation:

The text of the problem says that the skydiver is slowing down: this means that he has an acceleration, which is directed opposite to the motion of the skydiver. Since the motion is downward, the acceleration must be upward.

There are two forces acting on the skydiver: the gravity (downward) and the air resistance (upward). According to Newton's second law:

F=ma

the acceleration has the same direction of the net force, so the net force must also be upward: therefore, the air resistance must be greater than the gravity, so the arrow up for air resistance is longer than the arrow down for gravity.

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Hooke’s law describes the linear relationship between stress and strain through Young’s modulus. Given two materials under the s
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The material with higher modulus will stretch less than

The material with lower modulus

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Hooks law states that provided the elastic limit is not exceeded the extension e of a spring is directly proportional to the load or force attached

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How long will it take a car to travel a distance of 1km if it has an average speed of 60kph​
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Answer:

1÷60 h

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3 years ago
An element's atomic number is 34. How many protons would an atom of this element have?
Elena-2011 [213]

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2 years ago
An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I
oksano4ka [1.4K]

Answer:

The deviation in path is 4.39 \times 10^{-3}

Explanation:

Given:

Velocity v = 1 \times 10^{6} \frac{m}{s}

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Distance x = 1 \times 10^{-2} m

Mass of electron m = 9.1 \times 10^{-31} kg

Charge of electron q = 1.6 \times 10^{-19} C

Time taken to travel distance,

    t = \frac{x}{v}

    t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }

    t = 10^{-8} sec

Acceleration is given by,

  F = qE

ma = qE

   a = \frac{qE}{m}

   a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }

   a = 8.77 \times 10^{13} \frac{m}{s^{2} }

For finding the distance, we use kinematics equations.

   y = vt + \frac{1}{2}  at^{2}

Where v = 0 because here initial velocity zero

   y = \frac{1}{2} at^{2}

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   y = 4.39 \times 10^{-3} m

Therefore, the deviation in path is 4.39 \times 10^{-3}

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