Answer:
a)C2HBrClF3 = 197.35 g/mol
b)C12H14N2CL2 = 229.06g/mol
c)C8H10N4O2 = 194.22g/mol
d) CO(NH2)2=60.07 g/mol
e)C17H35CO2Na = 306.52 g/mol
Explanation:
Molar mass of a compound is equal to the sum of the atomic masses of the constituent elements.
a) C2HBrClF3
b) C12H14N2CL2
c) C8H10N4O2
d) CO(NH2)2
e) C17H35CO2Na
<span>pH = pKa + log ([base]/[acid]) = -log (3.5 x 10^-4) + log (0.040/.020) = 3.46 - 0.30 = 3.16</span>
The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
= 0.200 × 0.039 l
= 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be;
= (0.0156 × 1)/0.1
= 0.156 M
The main formula is as follow is explained in the attached file (please look at the examples)
the 1,3- butadiene is h2c=ch-ch=ch2, so we have
sp² sp² sp² sp²
h2c = ch - ch = ch2
<span>the hybridization of the carbon atoms is </span>sp² : trigonal planar
