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adoni [48]
3 years ago
9

What happens to pressure as temperature increases and temperature decreases

Chemistry
2 answers:
likoan [24]3 years ago
8 0

When temperature increases pressure also increases.

When temperature decreases pressure decreases.

That is why you have low tire pressure when it’s cold out

Tasya [4]3 years ago
3 0

Temperature and Pressure have a <u>direct relationship</u>!

When Temperature increases ↑

Pressure increases ↑

When Temperature decreases ↓

Pressure decreases ↓

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Need help setting the problem up
Sveta_85 [38]

Answer:

4.0 moles

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The following data were obtained from the question:

Volume (V) = 12L

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Temperature (T) = 205K

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Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

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When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C
natka813 [3]

Answer:

\Delta_{r}U of the reaction is -6313 kJ/mol

\Delta_{r}H of the reaction is -6312 kJ/mol

Explanation:

Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C

q_{cal}= C \times \Delta T

=5.861 \times 3.596 = 21.076\,kJ

q_{rxn}= -q_{cal}= -21.076\,kJ

\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol

Therefore, \Delta_{r}U of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter  is as follows.

C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)

Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5

\Delta_{r}H=\Delta E+ \Delta n. RT

=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol

Therefore, \Delta_{r}H of the reaction is -6312 kJ/mol.

3 0
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