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nikklg [1K]
2 years ago
13

Why does water that is frozen in an ice cube tray stay in the shape of a cube when it is

Physics
1 answer:
quester [9]2 years ago
6 0
The Answer is B : The water particles become locked in place.
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An upright spring with a 96g mass on it is compressed 2 cm. When
Alexeev081 [22]

Answer:

I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5

Explanation:

Use the m*g*h=1/2*k*x^2 equation

96*9.81*60=1/2*k*2^2

5650.56=2k

5650.56/2=2825.28N/m

8 0
3 years ago
A form of erosion in which particles of sand or dust rub across the surface of rocks.
gayaneshka [121]
The answer is B) Abrasion.
7 0
3 years ago
Read 2 more answers
A baseball pitcher throws a baseball horizontally at a linear speed of 49.4 m/s. Before being caught, the baseball travels a hor
RideAnS [48]

Answer:

v = 3.61 m/s

Explanation:

As we know that ball travels horizontal distance of 24.7 m with uniform speed 49.4 m/s

so we will have

t = \frac{x}{v_x}

t = \frac{24.7}{49.4}

t = 0.5 s

now in the same time ball is turned by angle

\theta = 52.7 rad

now we know that

\theta = \omega t

52.7 = \omega (0.5)

\omega = 105.4 rad/s

now the tangential speed of a point at equator is given as

v = r\omega

v = 0.0343(105.4)

v = 3.61 m/s

4 0
3 years ago
During an isothermal process, 10 j of heat is removed from an ideal gas. What is the work done by the gas in the process?
Black_prince [1.1K]

The work done in the isothermal process is 10 joule.

We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.

ΔU = 0

Hence,

ΔU = Q - W

0 = Q - W

Q = W

It means that the heat transferred is the same as the work done.

From the question above, we know that the heat transferred is 10 joule. Thus, the work done in the isothermal process is 10 joule.

Find more on isothermal at: brainly.com/question/17097259

#SPJ4

8 0
1 year ago
A 60 g ball of clay is thrown horizontally at 40 m/s toward a 1.5 kg block sitting at rest on a frictionless surface. the clay h
Bingel [31]
The solution for this problem is:
Let u denote speed. 

Equating momentum before and after collision: 
= 0.060 * 40 = (1.5 + 0.060) u 
= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
7 0
2 years ago
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