I believe this is what you have to do:
The force between a mass M and a point mass m is represented by

So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ =
G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ =
F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.
Answer:
D
Explanation:
During free fusion, the eyes converge or diverge in order to view a stereogram without a stereoscope.
Answer:
E
Explanation:
The police car is going to fast for the cop to hear and the same is with the speeder its who hears its highest pitch because it drives right past you and your not moving just standing on the cross walk