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Sophie [7]
3 years ago
9

The crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.259 of the speed of light.

but all is not lost! you launch a space torpedo toward the foe at 0.349 of the speed of light with respect to you. at what speed in kilometers per second does the enemy crew observe the torpedo approaching its spacecraft?
Physics
1 answer:
Vladimir79 [104]3 years ago
4 0
If you do not have to use relative physics but classic physics, this is how you solve it:

Speed of light = c = 3 * 10^5 km/s

Speed of your foe respect to you: 0.259c

Speed of the torpedo respect to you: 0.349c

Speed of the torpedo respect your foe: 0.349c - 0.259c = 0.09c

Conversion to km/s = 0.09 * 3.0 * 10^5 km/s = 27000 km/s

Note that this solution, using classic physics do not take into account time and space dilation.

Answer: 27000 km/s
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What is the frequency of a wave that has a period of 5 seconds
Alex17521 [72]

Answer:

0.20 Hz

Explanation:

Frequency is the reciprocal of the period. The period is 5 seconds, so the frequency is 1/(5 s) = 0.20 Hz.

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How far does a cyclist travel if she's going 6 m/s in 10 seconds?
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the answer is (b) 0.6

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3 years ago
A 180 meter long train, travelling at a constant speed, is passing a car driving on an adjacent lane at a speed of 72 km/h. Know
Lana71 [14]

Answer:

The velocity of the train is 82.8 km/h

Explanation:

The equation for the position of the train and the car is as follows:

x = x0 + v · t  

Where:

x = position at time "t".

x0 = initial position.

v = velocity.

t = time.

First, let´s calculate the distance traveled by the car in 60 s (1/60 h). Let´s place the origin of the frame of reference at the front of the train when it starts to pass the car so that the initial position of the car is 0 (x0 = 0 m):

x = 0 m + 72 km/h · (1/60) h

x = 1.2 km.

Then, if the whole train passes the car at that time, the position of the front of the train at that time will be 1.2 km + 0.18 km = 1.38 km.

Then using the equation of position we can obtain the velocity:

x = x0 + v · t

1.38 km = 0 m + v · (1/60) h

1.38 km / (1/60) h = v

v = 82.8 km/h

The velocity of the train is 82,8 km/h

The same result could be obtained using the rear of the train. You only have to identify where the rear is at t = 0 and where it is at t = 60 s.

Try it!

6 0
3 years ago
One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor
zhannawk [14.2K]

Answer:

Part a)

v = 16.52 m/s

Part b)

v = 7.47 m/s

Explanation:

Part a)

(a) when the large-mass object is the one moving initially

So here we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v

since this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}

v = \frac{(8.4\times 24 + 3.8\times 0)}{3.8 + 8.4}

v = 16.52 m/s

Part b)

(b) when the small-mass object is the one moving initially

here also we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v

Again this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}

v = \frac{(8.4\times 0 + 3.8\times 24)}{3.8 + 8.4}

v = 7.47 m/s

4 0
3 years ago
11 kg is a familiar weight for a bag of flour. You are baking cookies for a Save The Rain Forest fund drive. It takes 500 g of f
arlik [135]

Answer: 22 batches.

Explanation:

Given that 11 kg is a familiar weight for a bag of flour. Also, it is given that It takes 500 g of flour to make one batch of cookies.

How many batches of cookies can you make with one bag of flour

Let's first convert 11 kg into grams (g) by multiplying it by 1000

11 × 1000 = 11000 g

Divide 11000 by 500

11000/500 = 22

Therefore, 22 batches of cookies can be made with one bag of flour.

8 0
3 years ago
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