An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile at a constant acceleration of 1.96 m/s2 . The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s2
Find the total time required for the police car to over take the automobile.
Answer:
15.02 sec
Explanation:
The total time required for the police car to overtake the automobile is related to the distance covered by both cars which is equal from instant point of abreast.
So; we can say :

By using the second equation of motion to find the distance S;





where ;
u = 0





Recall that:



= 46.68 - 7.85 t -2.505 t² = 0
Solving by using quadratic equation;
t = -6.16 OR t = 3.02
Since we can only take consideration of the value with a positive integer only; then t = 3.02 secs
From the question; The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit;
Therefore ; the total time required for the police car to over take the automobile = 12 s + 3.02 s
Total time required for the police car to over take the automobile = 15.02 sec
Answer:
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class PhoneBook {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Map<String, String> map = new HashMap<>();
String name, number, choice;
do {
System.out.print("Enter name: ");
name = in.next();
System.out.print("Enter number: ");
number = in.next();
map.put(name, number);
System.out.print("Do you want to try again(y or n): ");
choice = in.next();
} while (!choice.equalsIgnoreCase("n"));
System.out.print("Enter name to search for: ");
name = in.next();
if (map.containsKey(name)) {
System.out.println(map.get(name));
} else {
System.out.println(name + " is not in the phone book");
}
}
}
Answer:
82.62%
Explanation:
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%