Rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3) in order o
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The question is incomplete, here is the complete question:
How many grams of zinc would be required to produce 9.65g of zinc hydroxide
Zn+2MnO₂+H₂O→Zn(OH)₂+Mn₂O₃
<u>Answer:</u> The mass of zinc required is 6.35 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of zinc hydroxide = 9.65 g
Molar mass of zinc hydroxide = 99.4 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
1 mole of zinc hydroxide is produced from 1 mole of zinc
So, 0.0971 moles of zinc hydroxide will be produced from = of zinc
Now, calculating the mass of zinc from equation 1, we get:
Molar mass of zinc = 65.4 g/mol
Moles of zinc = 0.0971 moles
Putting values in equation 1, we get:
Hence, the mass of zinc required is 6.35 grams
Answer:
Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.
Explanation:
Molarity of HCl solution = 0.1174 M
Volume of HCl solution = 83.15 mL = 0.08315 L
Moles of HCl = n
According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then 0.009762 mol of HCl will recat with:
Moles of Sodium carbonate = 0.004881 mol
Volume of the sodium carbonate containing solution taken = 1L
Concentration of sodium carbonate in the solution before the addition of HCl: