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cricket20 [7]
3 years ago
10

Rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3) in order o

f decreasing concentration of CO2.
~
I need to know how to physically find the percentages of CO2 in H2O2 & NaHCO3
Chemistry
1 answer:
Komok [63]3 years ago
6 0
Astronomers use chemical signatures to determine<span> the age and .... </span>Gas<span> mixtures that contain more than </span>4<span>% hydrogen in </span>air<span> are potentially explosive. ... water vapor, </span>carbon dioxide<span>, and several other </span><span>gases</span>
You might be interested in
Ans with solution...
Licemer1 [7]

Answer:

The answer to your question is:

Vol of NO2 = 11.19 L

Vol of O2 = 2.8 L

Explanation:

Data

N2O5 = 56 g

STP     T = 0°C = 273°K

           P = 1 atm

MW N2O5 = 216 g

Gases law = PV = nRT

Process

                   216 g of N2O5 ---------------- 1 mol

                     54 g               -----------------  x

                    x = (54 x 1) / 216

                    x = 0.25 mol of N2O5

                   2 mol of N2O5 -----------------  4 mol of NO2

                   0.25 mol          ------------------    x

                   x = (0.25 x 4) / 2 = 0.5 mol of NO2

                   V = nRT/P

                   V = (0.5)(0.082)(273) / 1 = 11.19 L

                   2 mol of N2O5 ----------------- 1 O2

                   0.25 N2O5 ----------------------  x

                   x = (0.25 x 1) / 2 = 0.125 mol

                   Vol = (0.125)((0.082)(273) / 1 = 2.8 L

3 0
4 years ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

8 0
3 years ago
The mole fraction of NaCl in an aqueous solution is 0.132. How many moles of water are present in 1 mole of this solution?
SOVA2 [1]
You could look at it this way.
1 mole of solution = 0.132 of NaCl + x
1 - 0.132 = 0.868 mols of water.

answer: 0.868 <<<< answer


7 0
3 years ago
Read 2 more answers
Use the unbalanced equation NH3+O2=NO+H2O to find the mole ratio between NH3 and H2O
spayn [35]

Answer:

2/3

Explanation:

4 0
3 years ago
Chemical equation for heat of formation of c25h52
Alexus [3.1K]
 its exothermic. exothermic means the reaction gives out heat. [exo meaning outside and thermic meaning heat] because its a combustion reaction, fire is there meaning lots of heat. 
endothermic means it takes in heat. a good example is ammonium and water (NH3 +H20) 
<span>most chemical reaction are exothermic</span>
8 0
4 years ago
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