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RoseWind [281]
3 years ago
8

How would the freezing point of seawater compare with that of pure water

Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0
Given that seawater freezes at a lower temperature than pure water because of the salts dissolved in it.
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Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?
arsen [322]

The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.

The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.

The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.

Learn more: brainly.com/question/22824409

4 0
2 years ago
The diagram shows the basis for forming which of the following?
Montano1993 [528]
The answer is prolly A or B
8 0
3 years ago
Choose all the right answers.
gayaneshka [121]
I think the answer is

Reduce friction

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8 0
2 years ago
What does lower case omega mean in physics?
Reil [10]
Angular Velocity is the answer
4 0
3 years ago
What is the volume of 23.4 grams of nitrogen gas at 750 mmHg and 28 degrees C
ratelena [41]

Answer:

V = 20.97 L

Explanation:

Given data:

Mass of nitrogen = 23.4 g

Pressure of gas = 750 mmHg (750/760 = 0.99 atm)

Temperature of gas = 28°C (28+273= 301K)

Volume of gas = ?

Solution:

First of all we will calculate the number  of moles of gas.

Number of moles = mass / molar mass

Number of moles = 23.4 g/ 28 g/mol

Number of moles = 0.84 mol

Now we will calculate the volume:

PV = nRT

V = nRT/P

R = general gas constant = 0.0821 atm.L/mol.K

V = 0.84 mol× 0.0821 atm.L/mol.K× 301 K /  0.99 atm

V = 20.76 L/0.99

V = 20.97 L

6 0
3 years ago
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