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RoseWind [281]
3 years ago
8

How would the freezing point of seawater compare with that of pure water

Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0
Given that seawater freezes at a lower temperature than pure water because of the salts dissolved in it.
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A pharmaceutical company is making a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount
iragen [17]

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100

Now We can obtain the percent yield as followed using the above formula:  

\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times  100

47\% = \frac{Actual \ yield \ Rate}{4860}

The value of the Actual yield Rate =47\% \times 4860

                                                        = \frac{47}{100} \times 4860 \\\\ = 2284.2 g

The Actual yield Rate= 2284.2 g.

3 0
3 years ago
Which example illustrates a chemical change
Svetllana [295]
Burning wood because heat indicates a chemical change
7 0
3 years ago
Read 2 more answers
A gas takes up a volume of 35 L, and has a pressure of 4.8 atm. What is the new pressure of
joja [24]

Answer:

7.3 atm

Explanation:

- Use the formula P1V1 = P2V2

- Rearrange formula and then plug in values.

- Hope this helped! Let me know if you need more help or a further explanation.

3 0
3 years ago
* The cost of table salt and table sugar is Rs 15 per kg.
Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63

6 0
2 years ago
PLEASE HELP WITH THESE 3 QUESTIONS
Alenkinab [10]

Answer:

i think this is the answer

Explanation:

C).50 ML

D)8.5 ph

E)weak acid,strong base,basic

8 0
2 years ago
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