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den301095 [7]
3 years ago
11

What happens to your blood glucose level if you do not eat lunch? is a testable question?

Chemistry
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

Causes the glucose level to drop

Tcecarenko [31]3 years ago
3 0
It is not a good test question
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What did sewage treatment in Ancient Rome and 19th century London have in common? How effective was this strategy and why?
anygoal [31]

Yea pretty much

Explanation:

4 0
3 years ago
How many liters of salt solution will be needed to provide 15 grams of salt if the concentration of the solution is 50 g/l?​
asambeis [7]

Answer:

.30 l

Explanation:

15g/50g/l= .3l

6 0
3 years ago
How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
lara [203]
<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

5 0
3 years ago
Which of the following is soluble in water?
Nina [5.8K]
I hope this answers helps it’s D
8 0
3 years ago
20 g of Allg is dissolved in water to produce a solution with a concentration of 2.007M. What is the volume of this solution in
Dafna1 [17]

Answer:

369 ml

Explanation:

Mass of Aluminium (Al) = 20 g

Molar concentration =  2.007M

Molar concentration = Number of moles / Volume

The relationship between mass and number of moles;

Number of moles = Mass / Molar mass

Number of moles = 20 / 27 = 0.741 mol

2.007  = 0.741  / Volume

Volume = 0.741 / 2.007 = 0.369 L

converting to millilitres by multiplying by 1000

Volume = 0.369 * 1000 = 369 ml

6 0
3 years ago
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