ANSWER: From this experiment, Jeff can conclude that the heat capacity of oil is lower than that of water which means that oil requires less energy per gram of liquid in order to change its temperature.
Explanation:
₁₄Si 1s²2s²2p⁶3s²3p².
Principal quantum number (n=3) have four electrons (3s²3p²).
2) ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.
Azimuthal quantum number (l=o) have seven electrons (1s²2s²3s²4s¹).
3) ₈₀Hg [Xe] 4f¹⁴5d¹⁰6s².
Principal quantum number (n=4) have thirty-two electrons (4s²4p⁶4d¹⁰4f¹⁴).
The principal quantum number is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.
Answer:
Comets develop a fuzzy, cloud-like shell called a coma, as well as a tail.
Explanation:
This feature of a comet develops when the celestial body passes close to a star such as the sun. The ice around the nucleus of the comet sublimates forming the coma around the comment (when hit by light photons as observed from the earth). The tails are also formed by the ice being pushed a bit behind the comet by light pressure.
Answer:
basic
Explanation:
ph>7 soits basic not acidic
Answer : The final temperature of the solution in the calorimeter is, ![31.6^oC](https://tex.z-dn.net/?f=31.6%5EoC)
Explanation :
First we have to calculate the heat produced.
![\Delta H=\frac{q}{n}](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Cfrac%7Bq%7D%7Bn%7D)
where,
= enthalpy change = 82.8 kJ/mol
q = heat released = ?
m = mass of
= 5.10 g
Molar mass of
= 110.98 g/mol
![\text{Moles of }CaCl_2=\frac{\text{Mass of }CaCl_2}{\text{Molar mass of }CaCl_2}=\frac{5.10g}{110.98g/mole}=0.0459mole](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DCaCl_2%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DCaCl_2%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DCaCl_2%7D%3D%5Cfrac%7B5.10g%7D%7B110.98g%2Fmole%7D%3D0.0459mole)
Now put all the given values in the above formula, we get:
![82.8kJ/mol=\frac{q}{0.0459mole}](https://tex.z-dn.net/?f=82.8kJ%2Fmol%3D%5Cfrac%7Bq%7D%7B0.0459mole%7D)
![q=3.80kJ](https://tex.z-dn.net/?f=q%3D3.80kJ)
Now we have to calculate the final temperature of solution in the calorimeter.
![q=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
where,
q = heat produced = 3.80 kJ = 3800 J
m = mass of solution = 100 + 5.10 = 105.10 g
c = specific heat capacity of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= initial temperature = ![23.0^oC](https://tex.z-dn.net/?f=23.0%5EoC)
= final temperature = ?
Now put all the given values in the above formula, we get:
![3800J=105.10g\times 4.18J/g^oC\times (T_2-23.0)](https://tex.z-dn.net/?f=3800J%3D105.10g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%28T_2-23.0%29)
![T_2=31.6^oC](https://tex.z-dn.net/?f=T_2%3D31.6%5EoC)
Thus, the final temperature of the solution in the calorimeter is, ![31.6^oC](https://tex.z-dn.net/?f=31.6%5EoC)