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den301095 [7]
2 years ago
11

What happens to your blood glucose level if you do not eat lunch? is a testable question?

Chemistry
2 answers:
MaRussiya [10]2 years ago
8 0

Answer:

Causes the glucose level to drop

Tcecarenko [31]2 years ago
3 0
It is not a good test question
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What is the scientific study of how matter and energy interact​
spayn [35]

Answer: Hope This Helps!

Explanation:

Physics is the scientific study of matter and energy and how they interact with each other. This energy can take the form of motion, light, electricity, radiation, gravity — just about anything, honestly.

8 0
2 years ago
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The fluid in a barometer (shown above) is mercury, Hg. Why point
PIT_PIT [208]

Answer:

Mercury responds to temperatures differently than water. When mercury is cold, the molecules bunch together, making it seem to be less liquid, and the opposite happens during heat.

Hope this helps!

5 0
3 years ago
Ba2+(aq)+SO42−(aq)→BaSO4(s)
adelina 88 [10]
I don’t know what the question is asking
4 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
A marble rolls off horizontally from the edge of table top 1.50 m above the floor. it strikes the floor 2.0 m from the base of t
GrogVix [38]

a. t=0.553 s

b. vox(horizontal speed) = 3.62 m/s

<h3>Further explanation</h3>

Given

h = 1.5 m

x = 2 m

Required

a. time

b. vo=initial speed

Solution

Free fall motion

a. h = 1/2 gt²(vertical motion=h=voyt+1/2gt²⇒voy = 0)

\tt t=\sqrt{\dfrac{2h}{g} }

t = √2h/g

t = √2.1.5/9.8

t=0.553 s

b. x=vox.t(horizontal motion)

\tt x=v_{ox}\times t

vox=x/t

vox=2/0.553

vox=3.62 m/s

3 0
2 years ago
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