Momentum before the hit:
p = mv = 0.01 * 300 + 1 * 0
Momentum after the hit:
p = 0.01 * 150 + 1 * v
Momentum is conserved:
0.01 * 300 = 0.01 * 150 + v
3 = 1.5 + v
v = 1.5
The velocity of the block after the collision is 1.5 m/s.
Answer:
76 m /s
Explanation:
maximum height, H = 19.7 m
Angle of projection, θ = 15 degree
Let u be the projectile launch speed
Use the formula of maximum height


u = 75.9199 = 76 m /s
Applied Force, Gravity Force, Normal Force, Friction Force, Air Resistance Force, Tension Force, Spring Force. I know this is more than four but I hope this helps :)