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kipiarov [429]
3 years ago
10

The average power dissipated by a resistor connected to a sinusoidal emf is 5.0 W.

Physics
1 answer:
loris [4]3 years ago
4 0

I this is tricky one sec.. I would go with b

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A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has
son4ous [18]
<span>. An object at an elevated position will have stored energy while not in motion potential energy  is given by  (m*h*g) or
 (weight*h) due to gravity.
so it is
potential energy only
socorrec toption is
B
hope it helps </span>
8 0
3 years ago
Read 2 more answers
I need help with these questions :<br>(see image )​
dem82 [27]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Height of Aeroplane = 500 meters

Speed of Aeroplane = 200 m/s

Acceleration due to gravity = g = 10m/s^2

time of package to reach the ground = t = ?

Horizontal distance = d = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the plane as the plane is just moving in horizontal direction. So the bomb fall and will travel forward.

Initial horizontal velocity is given by,

                                            V_{ix} = 200 ms{-1}

Initial vertical velocity is given by,

                                            V_{iy} = 0m/s

By the second equation of motion under gravity,

                                           H = V_{iy}t + \frac{1}{2}gt^2\\\\500 = (0)t + \frac{1}{2}x10xt^2 \\\\500 = 0 + 5t^2\\\\t^2 = \frac{500}{5}\\\\t^2 = 100\\\\t = 10 seconds

<h2>_____________________________________</h2>

<u>For horizontal distance(d)</u>:

Horizontal distance has no acceleration thus d is given by

                                          d = vt

                                          d = 200x10

                                          d = 2000 meters

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

                 

4 0
3 years ago
A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does an equally thick wire 6 m long, made
shusha [124]

Answer:

2.4 mm

Explanation:

Given that:

Initial Original length of the wire L = 3 mm

The stretch  of the first wire  ΔL= 1. 2 mm

The length of the second wire L'' = 6 mm

The stretch of the second wire ΔL'' = ???

Considering the Tension of the system; the Young modulus and the cross sectional remains constant ; as such:

\frac{Y}{Y''} = \frac{FL}{A \Delta L} *\frac{A \Delta L''}{FL''}

1= \frac{L   \Delta L''}{L'' \Delta L}

\Delta L''= \frac{L'' \Delta L  }{L}

\Delta L''= \frac{6 \ m * 1.2 \ mm  }{3 \ m}

\Delta L''=2.4  \ mm

Thus, the same material under the same tension stretches 2.4 mm

8 0
3 years ago
Read 2 more answers
The aorta is approximately 25 mm in diameter. The mean pressure there is about 100 mmHg and the blood flows through the aorta at
Ksenya-84 [330]

Answer:

Explanation:

25 mm diameter

r₁  = 12.5 x 10⁻³ m radius.

cross sectional area =  a₁

Pressure P₁  = 100 x 10⁻³ x 13.6 x 9.8 Pa

a )

velocity of blood v₁ = .6 m /s

Cross sectional area at blockade = 3/4 a₁

Velocity at blockade area = v₂

As liquid is in-compressible

a₁v₁ = a₂v₂

a₁ x .6 m /s  = 3/4 a₁ v₂

v₂ = .8m/s

b )

Applying Bernauli's theorem formula

P₁ + 1/2 ρv₁² =  P₂ +  1/2 ρv₂²

100 x 10⁻³ x 13.6 x10³x 9.8 + 1/2 X 1060 x .6² = P₂ +  1/2x 1060 x .8²

13328 +190.8 = P₂ + 339.2

P₂ = 13179.6 Pa

= 13179 / 13.6 x 10³ x 9.8 m of Hg

P₂ =  .09888 m of Hg

98.88 mm of Hg

8 0
3 years ago
How many joules of heat are needed to raise the temperature of 50.0 g of aluminum from 10°C to 110°C, if the specific heat of al
dusya [7]

Answer:

Heat required to raise the temperature of the aluminium is 4750 J

Explanation:

As we know that the heat energy required to raise the temperature of the aluminium is given as

Q = ms\Delta T

here we know that

m = 50 g

\Delta T = 110 - 10

\Delta T = 100 ^oC

so we have

Q = 50(0.95)(100)

Q = 4750 J

5 0
3 years ago
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