Hydrocarbons are carbon and hydrogen. Methane is CH4, and propane is C3H8. Methene is CH3, and propene is C3H6. Carbohydrates are hydrates of carbon. They <span>have the general formula (CH2O)x. thats how it differs
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Think of it as a balloon when you pump air into it it grows bigger but, if you put too much air into it what happens it pops because the pressure was too much for the balloon to withhold. That's the same with a basketball when you pump air into it the pressure pushing on the material increases. <span />
Answer:
0.641 moles of ethane
Explanation:
Based on the equation:
C2H6(g) + 7/2O2(g) → 2CO2(g) + 3H2O(l)
We can determine ΔH of reaction using Hess's law. For this equation:
<em>Hess's law: ΔH products - ΔH reactants</em>
ΔH = {2ΔHCO2 + 3ΔHH2O} - {ΔHC2H6}
<em>Pure monoatomic substances have a ΔH = 0kJ/mol; ΔHO2 = 0kJ/mol</em>
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ΔH = {2*-393.5kJ/mol + 3*-285.8kJ/mol} - {-84.7kJ/mol}
ΔH = -1559.7kJ/mol
That means when 1 mole of ethane is in combustion there are released 1559.7kJ of heat. To produce 1.00x10³kJ there are needed:
1.00x10³kJ * (1mole ethane / 1559.7kJ) =
<h3>0.641 moles of ethane</h3>
The correct option is: ALL OF THE ABOVE.
A neutralization reaction is one in which acid and base react together in order to produce salt and water. The water formed is as a result of hydrogen ion and the hydroxyl ion which combine together to produce water. When a solution is neutralized, it implies that the salt is formed from equal weights of acid and base.
Molar mass 496.4200 g/mol
Number of moles:
40 g x 1 mol / 496.4200 => 0.08057 moles
Volume in liters:
250.0 mL / 1000 => 0.25 L
Therefore:
M = moles / V
M = 0.08057 / 0.25
= 0.32228 M
hope this helps!
