Question

Consider the reaction between no and cl2 to form nocl: 2no(g)+cl2(g)⇌2nocl(g) a reaction mixture at a certain temperature initially contains only [no]= 0.65 m and [cl2]= 0.53. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m . part a find the value of the equilibrium constant (kc) at this temperature.

Answer 1

Answer:

Kc = 0.402.

Explanation:

• We can calculate Kc from the relation: Kc = [NOCl]² / [NO]²[Cl₂].

• [NOCl] = 0.30 M, [NO] = 0.65 M, and [Cl₂] = 0.53 M.

• Now, we can get Kc:

• Kc =  [NOCl]² / [NO]²[Cl₂] = (0.30 M)² / [(0.65 M)².(0.53 M)] = 0.402.