Mass and distance.
Hope this helps:)
A theory of chemical combination, first stated by John Dalton in 1803. It involves the following postulates: (1) Elements consist of indivisible small particles (atoms). (2) All atoms of the same element are identical; different elements have different types of atom. (3) Atoms can neither be created nor destroyed.
(Brainliest me)
Answer:
51.1 g NH3
The required chemical reaction is given by:
N2 + 3H2 --> 2NH3
4.5 mol H2 × (2 mol NH3/3 mol H2) = 3 mol NH3
molar mass of NH3 is 17.031 g/mol
3 mol NH3 × (17.031 g NH3/1 mol NH3) = 51.1 g NH3
Answer:
(a) OPTION E=4
b) option E C sp² + C p
Explanation:
DEGREE OF UNSATURATION = C -H/2 -X/2 +N/2 +1
X IS HALOGENS
5-5/2+1/2+1= 4
b) Ethene comprises of two sp2-hybridized carbon atoms (bound to each other by sigma and two atoms each with hydrogen). The remaining unhybridized carbon p orbitals form a pi bond, giving ethene reactivity
Answer:
N-ethyl-2-methylpropan-2-amine
Explanation:
In this case, we have to start with the <u>IR info</u>. The signal on 3400 cm^-1 indicates the presence of a <u>hydrogen bonded to the heteroatom</u>. In this case, we have nitrogen in the formula, so we will have the <u>amine group</u>.
On the other hand, we have to analyze the NMR info:
a) We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.
b) We have a triplet => This indicates the presence of <u>CH3 bonded to a CH2</u>.
c) We have a quartet => This indicates the presence of <u>CH2 bonded to a CH3</u>.
From b) and c) we can conclude that we have the <u>ethyl group</u> bonded to a nitrogen.
Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the <u>ter-butyl group</u>.
In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group