Volume of H₂O added = 175 ml
<h3>Further explanation</h3>
Given
100 gm of a 55% (M/M) and 20% (M/M) nitric acid solution
Required
waters added
Solution
starting solution
mass H₂O = 45%=45 g
%mass of H₂O in new solution = 100%-20%=80%
Can be formulated for %mass H₂O :
![\tt \dfrac{45+x}{100+x}=80\%\\\\45+x=0.8(100+x)\\\\45+x=80+0.8x\\\\35=0.2x\rightarrow x=175~g](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B45%2Bx%7D%7B100%2Bx%7D%3D80%5C%25%5C%5C%5C%5C45%2Bx%3D0.8%28100%2Bx%29%5C%5C%5C%5C45%2Bx%3D80%2B0.8x%5C%5C%5C%5C35%3D0.2x%5Crightarrow%20x%3D175~g)
For water mass=volume(density = 1 g/ml)
So volume added = 175 ml
Single replacement since the Mg combines with Cl2 and H is left alone
The answer is B as isotopes are different versions of the same chemical element containing the same amount of protons and electrons but different amounts of neutrons.
Hey there!
Atomic mass Bromine ( Br ) = 79.9 u
Therefore:
79.9 g Br --------------- 22.4 L ( at STP )
18.0 g Br --------------- volume ??
Volume Br = 18.0 * 22.4 / 79.9
Volume Br = 403.2 / 79.9
Volume Br = 5.046 L
hope this helps!
Answer:
The electronic configuration of the element with Atomic number 19 is 2,8,8,1. The element is potassium. It is an alkali metal with one valence electron.