Answer:
The bottle is labeled pure so it probably is pure.
Explanation:
Answer:
The given parameter for the solubility of NaNO₃ in H₂O are;
The maximum solubility of NaNO₃ in H₂O at 10°C = 78 g
1. If we have 50 g of NaNO₃ in 100 g of water at 10°C, the solution is;
Undersaturated
2. If we have exactly 78 g of NaNO₃ in 100 g of water at 10°C the solution is;
A saturated solution
3. If will add 80 g of NaNO₃ in 100 g of water at 10°C,
The excess NaNO₃ which cannot be dissolved will be observed as solids in the mixture
4) The quantity of NaNO₃ that can be dissolved in H₂O at 40°C = 94 g
If the solution containing 94 g of NaNO₃ at 40°C is cooled to 10C about 16 g of NaNO₃ will precipitate out of the solution and exist as solids in the mixture
Explanation:
1. An undersaturated is a solution that holds smaller amount of solute that it can hold at a given temperature
2. A saturated solution holds as much solute as it can dissolve at a given temperature
3. When more solutes are added to a saturated solution, the excess solution will remain in the solid form in the mixture
4) Cooling a saturated solution below the saturation temperature will result in the precipitation or crystallization of the excess solutes in the solution.
Answer:
No, and yes. As there is a finite amount of matter in the
universe, only so much can be converted to make energy. There will
be a limit, though it is a long, long way from where we are
Explanation:
For [Ni(en)³]²⁺ which is purple, the crystal field splitting energy is greater than the complex ion, [Ni(H₂O)₆]²⁺ which is green in color.
When a Lewis base id attached to the metal ion by covalent bond, then the complex ion is formed and when these complex ions are present with other ions of opposite charge or neutral charge, they will make complex compounds.
Answer:
How about......................IRON MAN
Explanation:
