The proton transfer reaction between Cyanide and water can be written as; X^- + H2O -----> HX + OH^-
<h3>What is a proton transfer reaction?</h3>
A proton transfer reaction is one in which a proton is moved from one chemical specie to another.It is in fact and acid - base reaction in the Brownstead - Lowry sense.
The proton transfer reaction between Cyanide and water can be written as(Let the cyanide ion be shown as X);
X^- + H2O -----> HX + OH^-
Learn more about proton transfer: brainly.com/question/861100?
Mass number (A) =protons (p+) + neutrons(n°)
The correct answers :
It increases with a decrease in the concentration of H₂(g).
It decreases with an increase in the concentration of S₂(g).
It decreases with an increase in the concentration of H₂(g).
<h3 /><h3>Further explanation</h3>
Forward reaction : rate to form product
In equilibrium :
The product decreases ⇒ system will move from left to right(forward reaction)
The product increases ⇒ system will move from right to left(reverse reaction)
Answer:
H₂O
Explanation:
Chemical equation:
C₅H₁₂ + O₂ → CO₂ + H₂O
Balanced chemical equation:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
The given reaction is combustion reaction. The balance equation shows that there are equal number of moles of carbon, hydrogen and oxygen on both side of equation thus it follows the law of conservation of mass.
Combustion reaction:
The reaction in which substance react with oxygen and produced carbon dioxide and water.
Mostly hydrocarbons burns in the presence of oxygen and form carbon dioxide and water.
According to Boyle's law, Volume is indirectly proportional to the pressure.
So, P1V1 = P2V2
Substitute the known values,
1 * 50 = 3 * V2
V2 = 50/3 = 16.67 mL
In short, Your Answer would be: 16.67 mL
Hope this helps!