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daser333 [38]
3 years ago
10

A compound is found to have a molar mass of 598 g/mol. if 35.8 mg of the compound is dissolved in enough water to make 175 ml of

solution at 25°c, what is the osmotic pressure of the resulting solution?
Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0
The computation for molarity is: 
(x) (0.175 L) = 0.0358 g / 598 g/mol 
x = 0.000342093 M 
Whereas the osmotic pressure calculation: 
pi = iMRT 
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K) 
pi = 0.0083655 atm 
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr 
which rounds off to 6.36 torr
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Answer:

THE NEW PRESSURE OF THE HELIUM GAS AT 2.98 L VOLUME IS 124.8 kPa.

AT AN INCREASE ALTITUDE, THERE IS A LOWER PRESSURE ENVIRONMENT AND THE HELIUM GAS PRESSURE DECREASES AND HENCE AN INCREASE IN VOLUME.

Explanation:

The question above follows Boyle's law of the gas law as the temperature is kept constant.

Boyle's law states that the pressure of a fixed mass of gas is inversely proportional to the volume, provided the temperature remains constant.

Mathematically, P1 V1 = P2 V2

P1 = 150 kPa = 150 *10^3 Pa

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P2 = P1 V1 / V2

P2 = 150 kPa * 2.48 / 2.98

P2 = 372 *10 ^3 / 2.98

P2 = 124.8 kPa.

The new pressure of the gas when at a height which increases the volume of the helium gas to 2.98 L is 124.8 kPa.

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3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!!!!
dangina [55]

Answer:

I think the answer is c!

Explanation:

Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule. hope this helps you!

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