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daser333 [38]
3 years ago
10

A compound is found to have a molar mass of 598 g/mol. if 35.8 mg of the compound is dissolved in enough water to make 175 ml of

solution at 25°c, what is the osmotic pressure of the resulting solution?
Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0
The computation for molarity is: 
(x) (0.175 L) = 0.0358 g / 598 g/mol 
x = 0.000342093 M 
Whereas the osmotic pressure calculation: 
pi = iMRT 
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K) 
pi = 0.0083655 atm 
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr 
which rounds off to 6.36 torr
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Answer:

b) It produces electrical current spontaneously.

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Answer:

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Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

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In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}

∴  mass of S in 2 moles of S: w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g

<em>Given reaction</em>: 2S + 3O₂ → 2 SO₃

<em>In this reaction, the limiting reagent is S</em>

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or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ <u><em>The amount of heat produced by 42.8 g S:</em></u>

x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ

\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J

(\because 1 kJ = 10^{3} J)

<u>Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

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Answer:

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