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Vladimir [108]
3 years ago
12

A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required

to compress it another 1 in.
Physics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

A spring whose spring constant is 200 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 inch.

Step 1 of 4

The force at any point during the deflection of the spring is given by,

where is the initial force

and x is the deflection as measured from the point where the initial force occurred.

The work required to compress the spring is

Therefore work required to compress the spring is

The work required to compress the spring in Btu is calculated by

Where 1Btu =778

The work required to compress the spring,  

eman Asked on February 19, 2018 in thermal fluid Sciences 4th solutions.

Explanation:

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Zolol [24]

Answer:

I don't know this answer at all

Explanation:

I don't know about these problems

6 0
3 years ago
A pair of slits separated by 1 mm, are illuminated with monochromatic light of wavelength 411 nm. The light falls on a screen 1.
Ilya [14]

Answer:

t = 0.192 \mu m

Explanation:

Path difference due to a transparent slab is given as

\Delta x = (\mu - 1) t

here we know that

\mu = 1.79

now total shift in the bright fringe is given as

Shift = \frac{D(\mu - 1)t}{d}

Also we know that the fringe width of maximum intensity is given as

\delta x = \frac{\lambda D}{d}

now we have

\frac{D}{d} = \frac{\delta x}{\lambda}

now the shift is given as

Shift = \frac{(\mu - 1) t \delta x}{\lambda}

given that the shift is

Shift = 0.37 \delta x

here we have

0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}

now plug in all values in it

0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}

t = 0.192 \times 10^{-6} m

t = 0.192 \mu m

3 0
3 years ago
The results of a recent television survey of American TV households revealed that 86 out of every 100 TV households have at leas
Lelechka [254]

Answer:

q = \dfrac{14}{100}

Explanation:

given,

86 out of every 100 TV households have at least one remote control

Probability of any material is calculated by.

Probability = \dfrac{favourable\ outcome}{Total\ outcome}

P(at\ least\ one\ remote\ control)=\dfrac{86}{100}

P(at\ least\ one\ remote\ control)=0.86

now, Calculating probability that at least one remote control

   q = 1 - 0.86

   q = 0.14

P(doesnot\ have\ at\ least\ one\ remote\ control)=\dfrac{14}{100}

q = \dfrac{14}{100}

7 0
3 years ago
The diffusion rate for a solute is 4.0 x 10^-11 kg/s in a solvent- filled channel that has a cross-sectional area of 0.50 cm^2 a
zlopas [31]

Answer:

s = 9.6\times 10^{-12}kg/s

Explanation:

Given:

Solute Diffusion rate  = 4.0 × 10⁻¹¹ kg/s

Area of cross-section = 0.50 cm²

Length of channel  =0.25 cm

Now for the new channel

Area of cross-section = 0.30 cm²

Length of channel  =0.10 cm

let the Solute Diffusion rate  of new channel = s

now equating the diffusion rate per unit volume for both the channels

\frac{4\times 10^{-11}}{0.50\times 0.25}=\frac{s}{0.30\times 0.10}

thus,

s = 9.6\times 10^{-12}kg/s

7 0
3 years ago
What is the acceleration of a 10kg pushed by a 5n force
Semenov [28]
Force equals mass times acceleration. Or:
F=ma
Plug it in:
5=10a
5/10=(10a)/10
.5m/s²=a
8 0
3 years ago
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