Answer:
, pfx = pix + Jx.
Explanation:
The momentum principle tells us that impulse transfers momentum to an object.
If an object has 2 kgm/s of momentum, a 1 kgm/s impulse delivered to the object
increases its momentum to 3 kgm/s. That is, pfx = pix + Jx.
Just as we did with energy, we can represent this “momentum accounting” with a
momentum bar chart. For example, the bar chart of FIGURE 11.6 represents the ball
colliding with a wall in Figure 11.4. Momentum bar charts are a tool for visualizing
an interaction
<u>The answer is not contained detail explanation, just a solution and the required values. </u>
All the details are in the pictures, the answers are marked with orange colour.
Note,
in the task no 20.:
![m_A - the \ mass \ of \ A; \ m_B-the \ mass \ of \ B \ balls.\\V_A \ and \ V_B-the \ velocities \ of \ the \ A&B \ balls \ before \ collision.\\V'_A \ and \ V'_B-the \ velocities \ of \ the \ A&B \ balls \ after \ collision.](https://tex.z-dn.net/?f=m_A%20-%20the%20%5C%20mass%20%5C%20of%20%5C%20A%3B%20%5C%20m_B-the%20%5C%20mass%20%5C%20of%20%5C%20B%20%5C%20balls.%5C%5CV_A%20%5C%20and%20%5C%20V_B-the%20%5C%20velocities%20%5C%20of%20%5C%20the%20%5C%20A%26B%20%5C%20balls%20%5C%20before%20%5C%20collision.%5C%5CV%27_A%20%5C%20and%20%5C%20V%27_B-the%20%5C%20velocities%20%5C%20of%20%5C%20the%20%5C%20A%26B%20%5C%20balls%20%5C%20after%20%5C%20collision.)
V - the velocity of the pair of the balls after collision.
in the task no 21:
m₁ - the mass of the copper ball; m₂ - the mass of the copper calorimeter; m₃ - the mass of the water; t₀ - the initial temperature of water in the copper calorimeter; θ - the final temperature in the calorimeter after the copper ball is transferred into a copper calorimeter; t₁ - the required initial temperature of the copper ball before it is transferred into the calorimeter.
Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
3.60 A = 3.60 coulombs of charge per second
(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge
1 coulomb of charge is carried by 6.25 x 10^18 electrons
Number of electrons =
(55.08 Coul) x (6.25 x 10^18 e/coul) = <em>3.4425 x 10^20 electrons</em>
Answer:
<h2>6000 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 2000 × 3
We have the final answer as
<h3>6000 kg.m/s</h3>
Hope this helps you